Question

Which system of equations can be used to solve the following problem? Each child ticket for a ride costs $3, while each adult ticket cost $5. If the ride collected a total of $150, and 40 tickets where sold, how many of each type of ticket were sold? Let c be the number of of child tickets and a be the number of of adult tickets.

A. 3a + 5c = 40
a + c = 150

B. 3c + 5a = 150
a + c = 40

C. 3c + 5a = 40
a + c = 150

D. 5c + 3a = 150
c + a = 40

Answer 1

will medel and fan

Answer 2

The answer is B i believe

Answer 3

Because A can't be it because the top equation is set to 40 when in reality it is suppose to be equal to 150, and the same goes for C, and D is wrong because they don't follow the order that the problem is written in

Answer 4

i just wanted an explanation

Answer 5

@harleygirl18 : Please read http://openstudy.com/code-of-conduct. You could be of much greater help to other students by helping them towards finding their own solutions. Kindly do not give away answers. Involve your student in the solution process!

Answer 6

but thanks

Answer 7

"Which system of equations can be used to solve the following problem? Each child ticket for a ride costs $3, while each adult ticket cost $5. If the ride collected a total of $150, and 40 tickets where sold, how many of each type of ticket were sold? Let c be the number of of child tickets and a be the number of of adult tickets. "

I favor approaching this by writing your own equations.
$3 and $5 are rates (how much money per ticket). Here, rate * number of tickets = total cost for that type of ticket.

Let x be the # of child tickets and a be the # of adult tickets. What's an expression for the total "take" for ticket sales?