Find the equation of a line that is perpendicular to y=3x-8 and intersects this line at its y intercept.
If the slope of one line is m, and you want the slope of a 2nd line which is perpendicular to the first, find it by taking the negative reciprocal of the slope, m, of the 1st line. You are given y=3x-8. What's the slope of this line? What's the negative of this slope? What's the negative reciprocal of this slope? Your answer is the slope of the new (perpendicular) line.
mathmale was helping. the first step is to find the slope of your equation y=3x-8 Do you know the slope ?
no i don't know the slope, I think thats whats confusing me the most.
oh, I'm thinking you were supposed to have learned it by now. but if you see y = m x + b where m and b are numbers (notice this matches your equation) the number in front of the x (it's "name" is m) is the slope and the "b" is the y-intercept in your equation, : y=3x-8 what is the slope ? i.e. what is the number in front of the x ?
oh ok so the slope is 3 and the y intercept is -8.
yes. that is good. Here is a graph of this line (notice it goes through the y-axis at x=0, y=-8) and it goes over 1 step and up 3 steps (that is what a slope of 3 means)
They want a line that is perpendicular. As math male was saying the slope of a line that is perpendicular (makes a right angle) is found by 1. "flipping" the slope 2. multiplying by -1 examples: slope is ½ , perpendicular slope is 2/1 * -1 or 2*-1 or -2 or -2 : think of it as -2/1 , now flip it,1/-2 or - ½ , now multiply by -1 to get ½ what is 3 when you flip it, and multiply by -1 ?
-1/3
so the perpendicular line, starting with the "generic" equation y= mx + b we know m is -⅓ \[ y= -\frac{1}{3} x+b\] we know the point (0,-8) is supposed to be on this line (because they tell us intersects this line at its y intercept i.e. at (0,-8) so put in 0 for x and -8 for y
you should get this: \[ -8= -\frac{1}{3}\cdot 0 + b\] now simplify the right side
what is -⅓ * 0 ?
0
so now you have -8= 0+b what is 0+b simplify to?
adding 0 to something does not change it. 0+1= 1 0+2= 2 0+b = b
so now its -8=b
which means b is -8 so we put in -8 for b in the equation \[ y= -\frac{1}{3} x+b\]
Ohh ok thank u so much this makes so much more sense now.
you should get \[ y= -\frac{1}{3}x-8\] Here is what the lines look like.
Now i get it thank u for helping me.
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