PLEASE HELP 1. 3^5x = 42
so is the question \[3^{5x} = 42\]
yes :)
ok... so the easiest thing to do is
take the log of both sides.... does that make sense..?
that what my teacher tried to teach me but i don't understand how :/
ok... so the log law you need to know about is the one that deals with powers base \[\log(a^b) = b \times \log(a)\] so the log of a number involving a power can be written as the power times the log of the
so you would have \[\log(3^{5x}) = \log(42)\] any ideas on how to rewrite the left hand side..?
5x log 3 ?
great so you have \[5x \times \log(3) = \log(42 log(3) and log(42) are just numbers...dividing both sides by log(3) and that will give you a value for 5x, then you can some for x. you make want to check to question to see if you need a decimal approximation or an exact value
oops should read \[5x \times \log(3) = \log(42)\] and it doesn't matter which type of logs you use... base e or base 10 you'll get the same answer
I'd expect the value of x is between .6 and .8.... probably around 0.7
so i divide in my calculator log 3/log 42
oh no wait its the other way around
no other way \[5x = \frac{\log(42)}{\log(3)}\] then divide the answer by 5
and then i divided that by 5 and the answer i got was 0.6804...
makes sense to me yo check you can use \[3^{5 \times 0.6804}\ and see if you get 42
yes its right. thank you for your help. mind helping with a few more?
well post them as new questions and if I'm still here I'll look at them. There are lots of people her who provide great help
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