Tickets to the movies cost $12 for adults and $8 for children. A group of 14 people went to the movies, and the tickets cost $136. The system of equations models this situation, where x is the number of adults and y is the number of children.

How many adults and how many children were in the group?

A.
9 adults and 5 children

B.
6 adults and 8 children

C.
4 adults and 10 children

D.
8 adults and 6 children

Question

Tickets to the movies cost $12 for adults and $8 for children. A group of 14 people went to the movies, and the tickets cost $136. The system of equations models this situation, where x is the number of adults and y is the number of children.
 
 
 
How many adults and how many children were in the group?
 
 A.
9 adults and 5 children
 
 B.
6 adults and 8 children
 
 C.
4 adults and 10 children
 
 D.
8 adults and 6 children

anonymous · Answer

the equation for this problem is: X+Y=14
                                                   12X +8Y=136

anonymous · Answer

can someone plz help me

wilsondanielle · Answer

this is more of a math question.

However : 

If X is the number of adults and Y is the number of children, you know there has to be a total of 14 (equation #1)

You also know that 12X + 8Y is equal to 136 (equation #2) because that is the amount that was send.

The first step would be to isolate for one of the variables.

From equation 1, X+Y=14. Therefore, X = 14-Y (and Y=14-X)

Plug in either variable into equation #2 and solve for the remaining variable.

$$12x+8(14-x)=136$$
$$12x + 8*14 - 8x =136$$
$$12x +112 - 8x = 136$$
$$(12-8)x +112 = 136$$
$$4x = 136-112$$
$$4x = 24$$
$$x = 24/4 = 6$$

Therefore, 6 adults and 8 (14-6) children attended the movie.

thesmartone · Answer

Please post this in the math subject. Thanks! http://www.openstudy.com/study#/groups/Mathematics