Divide.

16x3 - 8x2 + 4x4
------------
2x
A) 8x^2 - 4x + 2x^3
B) 8x^2 - 4 + 2x^3
C) 8x^3 - 4x + 2x^3
D) 8x^2 - 4x + 2x

Question

Divide.

16x3 - 8x2 + 4x4
------------
2x
A)	8x^2 - 4x + 2x^3	
B)	8x^2 - 4 + 2x^3	
	C)	8x^3 - 4x + 2x^3	
D)	8x^2 - 4x + 2x

neonumbrella5115 · Answer

Have you learned the synthetic division or long division method?

heart_offire · Answer

well i learned how to just break it apart in three since there is three numbers on top and one at the bottom so it would be 16x^3/2x etc.

tkhunny · Answer

Super.  Then do that.

neonumbrella5115 · Answer

Interesting.  I didn't learn it that way however I think I can help you do specifically this problem the way you want.  
So when you divide the expression you said in the post above, you get 8x^2, but that doesn't help you narrow down your choices.  Right?

heart_offire · Answer

well i did that but it got confusing.......right @neonumbrella5115

tkhunny · Answer

Demonstrate.

heart_offire · Answer

my method doesnt always work with every equation like this one

neonumbrella5115 · Answer

So next, you would do -8x^2/ 2x and you would get: @heart_offire

heart_offire · Answer

4x^2

neonumbrella5115 · Answer

Almost, since you are dividing x^2 by an x there would only be one x in your answer.

heart_offire · Answer

oh.. thought they stay the same since its division

neonumbrella5115 · Answer

That's a mistake many people make, so no worries!  When you're working with dividing exponents you subtract the exponent #.  Example x^6/x^3 is x^3
So you want to try the last one on your own?

heart_offire · Answer

2x^3

heart_offire · Answer

4x^4/2x=2x^3

tkhunny · Answer

Division always works.

$\dfrac{16x^{3} - 8x^{2} + 4x^{4}}{2x} = \dfrac{2x(8x^{2} - 4x +2x^{3})}{2x} = \dfrac{2x}{2x}(8x^{2} - 4x +2x^{3})$

neonumbrella5115 · Answer

Yup!  So the only choice with 4x and 2x^3 and 8x^2 is...

heart_offire · Answer

A

heart_offire · Answer

that was my first original chioce but i clicked C instead i have no idea why though

neonumbrella5115 · Answer

@tkhunny That's how I usually solve these kinds of problems, as it always works no matter what.  It also is very simple, once you get the hang of it.  If you continue to do problems like these @heart_offire I would suggest learning the divison method above^^

neonumbrella5115 · Answer

A is correct!!  Good job!  If you need anymore help just tag me!

heart_offire · Answer

^sure i'll tag you with the next problem im having trouble solving