help please
\[Explain why (-3)^{2\neq}-3^{2}, but (-2)^{3}=-2^{3}\]
It's my daughters homework I just don't know how to explain it lol
the exponent tells us how many times we should multiply the base by itself
\[\rm (-x)^2\] exponent to the -x not just x which can be written as -x times - x =+x - times - = positive
-x^2 means just x to the 2 power not the sign \[\rm -x^2 \rightarrow -1x^2 = -1*x*x\] negative times positive = negative
\[\rm \color{ReD}{(-1x)^2}= -1x*-1x = 1x\] vs \[\rm -1x^2 = -1x*1x\] x is same as 1x ( #1 is invisible )
make sense ?
I don't understand what she would write still lol
when you take `even` power of a negative number you will get positive answer \[\rm (-4)^4 = positive \]bec (-4)^4= -4 times -4 times -4 times -4 = positive and when you take odd power of a negative number you will get negative answer \[\rm (-4)^3= negative \] -4 times -4 times -4= negative
OK...
\[a \times a \times a = a ^{3}\] \[(-3)^{2 } =(-3) \times (-3) = 3^{2}\]
\[(-2) \times (-2) \times (-2) = - [2 \times 2 \times 2]= - 2^{3}\]
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