Question

A line is perpendicular to the line 2x-4y+7=0 and that passes through the point P(7,2). Determine the equation of this line in Cartesian form.

Answer 1

find the slope of the given line by bringing it to the form y=mx+c

to find slope of the new line,
use this: if m1 and m2 are slopes of two perpendicular lines, then m1*m2=-1

Answer 2

so is the direction vector be (4,2) like we are goona flip because its perpendicular

Answer 3

@baru @Abhisar @brennerbussy2001

Answer 4

@Zale101 @nincompoop @elvisiscool69 @hartnn @They_Call_Me_Narii @lυἶცἶ0210 @Whitemonsterbunny17 @retirEEd

Answer 5

if you are doing it that way..
the slope of the new line is \(<f_x,f_y>\)=<2,-4>
(because the gradient is perpendicular to the level curve)

Answer 6

not slope.. i meant direction vector.
direction vector of the new line is <2,-4>

Answer 7

by which method are you trying to solve this question?
if its by vectors and dot product, you have to flip <2,-4> to get <4,2> because <4,2> is perpendicular to the "required line"

then <4,2> \(\cdot\) <x-7 , y-2> = 0 (dot product of perpendicular vectors is zero)
expand that to get the required equation

Answer 8

wait so the given direction vector is (2,-4) and know they want the line to be perpendicular right ? @baru @YanaSidlinskiy @hartnn @Thadds2003 @Ghostgate @AlexandervonHumboldt2 @nincompoop @Kitten_is_back

Answer 9

@Luigi0210

Answer 10

@inkyvoyd @ichliebedich @brennerbussy2001 @abi_carter @lυἶცἶ0210

Answer 11

@ParthKohli @mukushla

Answer 12

@moo963

Answer 13

are you in 11th grade?

Answer 14

@kayt131

Answer 15

@ParthKohli no i am in 12

Answer 16

hmm uh may i ask, what grade are you in?

Answer 17

@kayt131 12

Answer 18

oh... idk if i can help you sorry, im in 8th but ill still try.

Answer 19

@kayt131 its ok

Answer 20

yeah i don't understand this. I haven't learned this yet... thanks for asking for my help tho, i would have helped if I understood. sorry...