Mathematics
7 Online
OpenStudy (anonymous):
Help!
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OpenStudy (anonymous):
OpenStudy (misty1212):
HI!!
OpenStudy (anonymous):
Hi.
OpenStudy (misty1212):
you see where the line crosses the y axis?
OpenStudy (anonymous):
Yes
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OpenStudy (misty1212):
at what number ?
OpenStudy (anonymous):
2?
OpenStudy (misty1212):
yes
OpenStudy (misty1212):
that means the number out at the end is \(+2\)
OpenStudy (anonymous):
So, A??
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OpenStudy (misty1212):
yes
OpenStudy (anonymous):
Explain Howard?
OpenStudy (misty1212):
actually the answer is not D
OpenStudy (misty1212):
if \(x=0\) you have \(y=2\) so it is \(y=x+2\)
OpenStudy (anonymous):
Yeah, because the 2 is positive and not negitive right?
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OpenStudy (howard-wolowitz):
ok @misty1212 is right ignore me
OpenStudy (anonymous):
Help me with one more? It's a different equation.
OpenStudy (misty1212):
ok
OpenStudy (anonymous):
OpenStudy (misty1212):
it is definitely not the first one since if you put \(x=11\) you get \[y=4\times 11-3=44-3=41\] not \(5\)
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OpenStudy (misty1212):
all the other choices have \((5,11)\) so we need to check the second ones
OpenStudy (anonymous):
okay
OpenStudy (misty1212):
lets check \((3,2)\) which means if \(x=3\) you should have \(y=2\)
OpenStudy (misty1212):
the check is , is \[3\times 3-4=2\]?
OpenStudy (anonymous):
So B?
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OpenStudy (misty1212):
no not B
OpenStudy (misty1212):
since \[3\times 3-4=9-4=5\] not \(2\)
OpenStudy (anonymous):
d? or a?
OpenStudy (misty1212):
you have to put in the first number and see if you get the second
OpenStudy (misty1212):
so lets try D
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OpenStudy (misty1212):
since we know it is not A
OpenStudy (misty1212):
is \[3\times 2-4=2\]?
OpenStudy (anonymous):
yes
OpenStudy (misty1212):
then \((2,2)\) is on the graph, so D
OpenStudy (anonymous):
thank you