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Mathematics 7 Online
OpenStudy (anonymous):

Help!

OpenStudy (anonymous):

OpenStudy (misty1212):

HI!!

OpenStudy (anonymous):

Hi.

OpenStudy (misty1212):

you see where the line crosses the y axis?

OpenStudy (anonymous):

Yes

OpenStudy (misty1212):

at what number ?

OpenStudy (anonymous):

2?

OpenStudy (misty1212):

yes

OpenStudy (misty1212):

that means the number out at the end is \(+2\)

OpenStudy (anonymous):

So, A??

OpenStudy (misty1212):

yes

OpenStudy (anonymous):

Explain Howard?

OpenStudy (misty1212):

actually the answer is not D

OpenStudy (misty1212):

if \(x=0\) you have \(y=2\) so it is \(y=x+2\)

OpenStudy (anonymous):

Yeah, because the 2 is positive and not negitive right?

OpenStudy (howard-wolowitz):

ok @misty1212 is right ignore me

OpenStudy (anonymous):

Help me with one more? It's a different equation.

OpenStudy (misty1212):

ok

OpenStudy (anonymous):

OpenStudy (misty1212):

it is definitely not the first one since if you put \(x=11\) you get \[y=4\times 11-3=44-3=41\] not \(5\)

OpenStudy (misty1212):

all the other choices have \((5,11)\) so we need to check the second ones

OpenStudy (anonymous):

okay

OpenStudy (misty1212):

lets check \((3,2)\) which means if \(x=3\) you should have \(y=2\)

OpenStudy (misty1212):

the check is , is \[3\times 3-4=2\]?

OpenStudy (anonymous):

So B?

OpenStudy (misty1212):

no not B

OpenStudy (misty1212):

since \[3\times 3-4=9-4=5\] not \(2\)

OpenStudy (anonymous):

d? or a?

OpenStudy (misty1212):

you have to put in the first number and see if you get the second

OpenStudy (misty1212):

so lets try D

OpenStudy (misty1212):

since we know it is not A

OpenStudy (misty1212):

is \[3\times 2-4=2\]?

OpenStudy (anonymous):

yes

OpenStudy (misty1212):

then \((2,2)\) is on the graph, so D

OpenStudy (anonymous):

thank you

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