Question

help?

Answer 1

A factory can produce two products, x and y, with a profit approximated by P = 14x + 22y – 900. The production of y can exceed x by no more than 200 units. Moreover, production levels are limited by the formula x + 2y ≤ 1400. What production levels yield maximum profit?

A. identify the vertices of the feasible region
B. what production level yield the maximum profit, and what is the maximum profit?

Answer 2

@danica518 ?

Answer 3

okay graph these functions first

Answer 4

what does x+2y<=1400 look like put it in y=mx+b form, that will help

Answer 5

hint:
I can model the statement: "The production of y can exceed x by no more than 200 units.", with this equation:
\[y - x \leqslant 200\]

Answer 6

Wait so can I put this on a graphing calculator?

Answer 7

for part A, we have to solve this system:
\[\left\{ \begin{gathered}
x + 2y = 1400 \hfill \\
y - x = 200 \hfill \\
\end{gathered} \right.\]

Answer 8

Okay one moment! thank you

Answer 9

with the conditions:
\[x \geqslant 0,\;y \geqslant 0\]

Answer 10

x=1000/3 and y= 1600/3???

Answer 11

I got this region:

Answer 12

then we have to maximize such function inside that region

Answer 13

do you now differential calculus?

Answer 14

No! Im not taking cal!

Answer 15

I'm thinking on your question...

Answer 16

yep im confused as well//

Answer 17

I think that the value which maximizes the function \(P(x,y)\) is at
\(P=(1000/3,\; 1600/3)\), namely when:
\(x=1000/3\), and \(y=1600/3\)

Answer 18

Thats the final statement? well okay. thanks

Answer 19

please wait a moment

Answer 20

ok

Answer 21

I confirm that it is at point P

Answer 22

I have applied an elementary procedure

Answer 23

Alrighty! Thank you!

Answer 24

:)