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Mathematics 6 Online
OpenStudy (isuckatschool43):

Please help me!!! I will fan and medal!

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

@imqwerty please help no one will answer

imqwerty (imqwerty):

hello :)

OpenStudy (isuckatschool43):

hi

imqwerty (imqwerty):

direct variation between \(x\) and \(y\) means that the equation must be of this form-> \(\large y=kx\) where \(k\) maybe any number :)

imqwerty (imqwerty):

try to answer it now :)

OpenStudy (isuckatschool43):

so it has to be either A or D since those arent in that format?

imqwerty (imqwerty):

Why do you think that D is not in that format?

OpenStudy (isuckatschool43):

Because it is dividing?

imqwerty (imqwerty):

okay lets compare the standard form with the option D Standard form-> \(\color{violet}{\large y=kx}\) Option D-----> \(\color{violet}{\large y= \Large\frac{x}{9}}\) or we can say-> \(\color{violet}{\large y= \Large\frac{1}{9}\times x }\) try figuring out what will be our \(k|) in option D

OpenStudy (isuckatschool43):

the k is 1/9?

imqwerty (imqwerty):

yes :) now read that definition of direct variation i wrote in beginning it says k can be any number so will option D be direct or not

OpenStudy (isuckatschool43):

direct

imqwerty (imqwerty):

:) and we need to find the option which does not shows direct variation what do u think it will be

OpenStudy (isuckatschool43):

A

imqwerty (imqwerty):

bingo correct :D

OpenStudy (isuckatschool43):

Awesome thank you. I have a few more however. Do you have time? :)

imqwerty (imqwerty):

yeah i hav some time :)

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

I think A and B

imqwerty (imqwerty):

i forgot to add one thing in the definition it is-> that \(k\) must be positive number if \(k\) is negative then its not a direct variation

OpenStudy (isuckatschool43):

Oh okay that helps a lot

imqwerty (imqwerty):

and in a direct variation -> as we increase the value of \(x\) the value of \(y\) will also increase simultaneously

OpenStudy (isuckatschool43):

okay. so i think it cant be B or D because they are both negative, right?

OpenStudy (isuckatschool43):

@imqwerty ?

imqwerty (imqwerty):

sry it was lagging

imqwerty (imqwerty):

okay heres a more refined definition of direct variation-> direct variation between \(x\) and \(y\) is of the form-> \(\large y=kx+c\) \(c\)--> any constant number [can be positive or negative] \(k\)--> any constant number[can only be positive] :) if the above rules aren't satisfied then relation is not direct relationship

imqwerty (imqwerty):

now try to figure the options out :)

OpenStudy (isuckatschool43):

So A,C, and D?

imqwerty (imqwerty):

c can also be 0

OpenStudy (isuckatschool43):

how can it be 0?

imqwerty (imqwerty):

okay :) we know that basically direct variation means that as we increase \(x\) , \(y\) must also increase agreed?

OpenStudy (isuckatschool43):

yeah

imqwerty (imqwerty):

now we gotta prove that \(y=kx+0\) is a direct variation and we know that \(k\) is some positive number

imqwerty (imqwerty):

do you agree that \(y=kx\) will be a line?

OpenStudy (isuckatschool43):

yes

imqwerty (imqwerty):

can you tell what will be the slope of this line

OpenStudy (isuckatschool43):

not really, i dont know how to find slope without points

OpenStudy (isuckatschool43):

all i know is that it has to be a positive slope

imqwerty (imqwerty):

why did you say that? :)

OpenStudy (isuckatschool43):

because a direct slope has to be positive or it wont be direct

imqwerty (imqwerty):

:) why did you say it to be direct

OpenStudy (isuckatschool43):

im confused now

imqwerty (imqwerty):

okay :) so you know that if \(y=kx\) has a direct slope then the slope will be positive right?

OpenStudy (isuckatschool43):

yep

imqwerty (imqwerty):

are you familiar with slope intercept form of line? :)

OpenStudy (isuckatschool43):

a little bit

imqwerty (imqwerty):

okay this is it-> \(y=mx+c\) where \(m\)-->slope of line \(c\)-->y intercept of line

imqwerty (imqwerty):

now try to find the slope of \(y=kx\) by comparing it with the slope intercept form

OpenStudy (isuckatschool43):

c=0 because it intercepts at (0,0) right

imqwerty (imqwerty):

yes correct :)

OpenStudy (isuckatschool43):

y=2x+0?

imqwerty (imqwerty):

why did u put that 2 there? you just have to find the value of \(m\) [slope] in this equation-> \(y=kx\) :)

OpenStudy (isuckatschool43):

wait, can i just put in k as m?

imqwerty (imqwerty):

yes :) so your slope becomes \(k\)

imqwerty (imqwerty):

and you know that \(k\) is positive so our slope is positive what will you say about the equation :) direct or indirect

OpenStudy (isuckatschool43):

direct

imqwerty (imqwerty):

so now we can say that \(c\) = 0 can work :) for \(y=kx+c\) where \(k\) is positive constant

OpenStudy (isuckatschool43):

ok

imqwerty (imqwerty):

okay so now use that definition above to figure out direct and indirect relation ships

OpenStudy (isuckatschool43):

for the answers?

imqwerty (imqwerty):

yes try to find the answer now :)

OpenStudy (isuckatschool43):

I believe it is A and D, and maybe C.

imqwerty (imqwerty):

correct!!! :D

OpenStudy (isuckatschool43):

Okay, I totally get this now. Thank you

imqwerty (imqwerty):

np :)

OpenStudy (isuckatschool43):

You rock, mainly because we were here a long time but you kept helping, and I don't see those types of people on here that often. :)

imqwerty (imqwerty):

you rock as well (B

OpenStudy (isuckatschool43):

bye

imqwerty (imqwerty):

c ya :)

OpenStudy (chantysquirrel1129**):

mhm, good job qwertay :3

OpenStudy (isuckatschool43):

Somehow it was A and B????

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