Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (isuckatschool43):
OpenStudy (isuckatschool43):
@imqwerty please help no one will answer
imqwerty (imqwerty):
hello :)
OpenStudy (isuckatschool43):
hi
imqwerty (imqwerty):
direct variation between \(x\) and \(y\) means that the equation must be of this form-> \(\large y=kx\)
where \(k\) maybe any number :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
try to answer it now :)
OpenStudy (isuckatschool43):
so it has to be either A or D since those arent in that format?
imqwerty (imqwerty):
Why do you think that D is not in that format?
OpenStudy (isuckatschool43):
Because it is dividing?
imqwerty (imqwerty):
okay lets compare the standard form with the option D
Standard form-> \(\color{violet}{\large y=kx}\)
Option D-----> \(\color{violet}{\large y= \Large\frac{x}{9}}\) or we can say-> \(\color{violet}{\large y= \Large\frac{1}{9}\times x }\)
try figuring out what will be our \(k|) in option D
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (isuckatschool43):
the k is 1/9?
imqwerty (imqwerty):
yes :)
now read that definition of direct variation i wrote in beginning
it says k can be any number so will option D be direct or not
OpenStudy (isuckatschool43):
direct
imqwerty (imqwerty):
:) and we need to find the option which does not shows direct variation
what do u think it will be
OpenStudy (isuckatschool43):
A
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
bingo correct :D
OpenStudy (isuckatschool43):
Awesome thank you.
I have a few more however.
Do you have time? :)
imqwerty (imqwerty):
yeah i hav some time :)
OpenStudy (isuckatschool43):
OpenStudy (isuckatschool43):
I think A and B
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
i forgot to add one thing in the definition
it is-> that \(k\) must be positive number
if \(k\) is negative then its not a direct variation
OpenStudy (isuckatschool43):
Oh okay that helps a lot
imqwerty (imqwerty):
and in a direct variation -> as we increase the value of \(x\) the value of \(y\) will also increase simultaneously
OpenStudy (isuckatschool43):
okay. so i think it cant be B or D because they are both negative, right?
OpenStudy (isuckatschool43):
@imqwerty ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
sry it was lagging
imqwerty (imqwerty):
okay heres a more refined definition of direct variation->
direct variation between \(x\) and \(y\) is of the form->
\(\large y=kx+c\)
\(c\)--> any constant number [can be positive or negative]
\(k\)--> any constant number[can only be positive]
:) if the above rules aren't satisfied then relation is not direct relationship
imqwerty (imqwerty):
now try to figure the options out :)
OpenStudy (isuckatschool43):
So A,C, and D?
imqwerty (imqwerty):
c can also be 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (isuckatschool43):
how can it be 0?
imqwerty (imqwerty):
okay :)
we know that basically direct variation means that as we increase \(x\) , \(y\) must also increase
agreed?
OpenStudy (isuckatschool43):
yeah
imqwerty (imqwerty):
now we gotta prove that \(y=kx+0\) is a direct variation and we know that \(k\) is some positive number
imqwerty (imqwerty):
do you agree that \(y=kx\) will be a line?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (isuckatschool43):
yes
imqwerty (imqwerty):
can you tell what will be the slope of this line
OpenStudy (isuckatschool43):
not really, i dont know how to find slope without points
OpenStudy (isuckatschool43):
all i know is that it has to be a positive slope
imqwerty (imqwerty):
why did you say that? :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (isuckatschool43):
because a direct slope has to be positive or it wont be direct
imqwerty (imqwerty):
:) why did you say it to be direct
OpenStudy (isuckatschool43):
im confused now
imqwerty (imqwerty):
okay :) so you know that if \(y=kx\) has a direct slope then the slope will be positive right?
OpenStudy (isuckatschool43):
yep
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
are you familiar with slope intercept form of line? :)
OpenStudy (isuckatschool43):
a little bit
imqwerty (imqwerty):
okay this is it->
\(y=mx+c\)
where \(m\)-->slope of line
\(c\)-->y intercept of line
imqwerty (imqwerty):
now try to find the slope of \(y=kx\) by comparing it with the slope intercept form
OpenStudy (isuckatschool43):
c=0 because it intercepts at (0,0) right
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
yes correct :)
OpenStudy (isuckatschool43):
y=2x+0?
imqwerty (imqwerty):
why did u put that 2 there?
you just have to find the value of \(m\) [slope] in this equation-> \(y=kx\) :)
OpenStudy (isuckatschool43):
wait, can i just put in k as m?
imqwerty (imqwerty):
yes :)
so your slope becomes \(k\)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
and you know that \(k\) is positive
so our slope is positive
what will you say about the equation :) direct or indirect
OpenStudy (isuckatschool43):
direct
imqwerty (imqwerty):
so now we can say that \(c\) = 0
can work :) for \(y=kx+c\)
where \(k\) is positive constant
OpenStudy (isuckatschool43):
ok
imqwerty (imqwerty):
okay so now use that definition above to figure out direct and indirect relation ships
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (isuckatschool43):
for the answers?
imqwerty (imqwerty):
yes try to find the answer now :)
OpenStudy (isuckatschool43):
I believe it is A and D, and maybe C.
imqwerty (imqwerty):
correct!!! :D
OpenStudy (isuckatschool43):
Okay, I totally get this now. Thank you
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
np :)
OpenStudy (isuckatschool43):
You rock, mainly because we were here a long time but you kept helping, and I don't see those types of people on here that often. :)
imqwerty (imqwerty):
you rock as well (B
OpenStudy (isuckatschool43):
bye
imqwerty (imqwerty):
c ya :)
Still Need Help?
Join the QuestionCove community and study together with friends!