Need assistance in three radical problems. http://prntscr.com/9mwxgw

Question

chantysquirrel1129** · Answer

mhm c:

imqwerty · Answer

:) 
$$\left( \frac{ \sqrt{2}+\sqrt{6} }{ \sqrt{2+\sqrt{3}} } \right)^2=\frac{ \left( \sqrt{2}+\sqrt{6} \right)^2 }{2+\sqrt{3}  }$$

try multiplying and dividing by $(2-\sqrt{3})$   and then simplify :)

goldphenoix · Answer

I solve the first and third already. Thanks for the help though.
I'm stump on the second one.  =/ @imqwerty

imqwerty · Answer

okay :)
try multiplying and dividing the  $\large 40-20\sqrt{6}$  inside bracket with $\large 40+20\sqrt{6}$

goldphenoix · Answer

I didn't understand it =/ Will this method work?

imqwerty · Answer

no thats not correct 
what i meant was to do this->
$$\sqrt[4]{40+20\sqrt{6}}+\sqrt[4]{40-20\sqrt{6}\times \frac{( 40+20\sqrt{6}) }{ (40+20\sqrt6) }}$$

goldphenoix · Answer

Instead of 40, then number is suppose to be 49 right? o_O

imqwerty · Answer

oh sry sry yes that must be 49

goldphenoix · Answer

The inbuilt equation is giving me a headache. So the radical on the right has a value of $$\sqrt[4]{40-20 \sqrt6}$$ 
Yeah?

goldphenoix · Answer

OHHH. Is the value 0?

goldphenoix · Answer

Wait. Let me think this through >_>

goldphenoix · Answer

|dw:1452119688985:dw|
What am I doing ._.