Help with #26
well you need to arrange it first into standard form and then take it from there
Isn't #26 already in standard form?
no
it would be difficult for you to factor if you do not make that into \(ax^3+bx^2+cx = 0 \)
make it quick, this should be like clock work
Ok well would the final answer be x = -1/2 - √37/2 , 0 , -1/2 , √37/2 and 3 real roots?
WTH laughing hysterically inside my head you did not even show you go got that
can you just do what I say first?
nin I just needed my answer checked
so show your solution
how did you get those answer?
3x^3 + 3x^2 - 27x = 0 3x(x^2 + x - 9) = 0 x = 0 x^2 + x = 9 x^2 + x + (1/2)^2 = 9 + 1/4 (x + 1/2)^2 = 37/4
x + 1/2 = ±√37/2 x = 1/2(-1 ± √37) x = -1/2 - √37/2 , 0 , -1/2 , √37/2 w 3 real roots.
why did you make it like this x^2 + x = 9
Idk I was trying to show every step even nuanced ones
Was my answer right or wrong
IDK
yes it is correct
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