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Mathematics 12 Online
OpenStudy (iwanttogotostanford):

really don't get this question, please help!

OpenStudy (iwanttogotostanford):

@campbell_st

OpenStudy (iwanttogotostanford):

but, not sure if its correct

OpenStudy (campbell_st):

what slope did you get...?

OpenStudy (campbell_st):

B looks to be correct

OpenStudy (anonymous):

I agree that seems to B correct.

OpenStudy (iwanttogotostanford):

@BigPoppa117 @campbell_st

OpenStudy (campbell_st):

ok... so the question is \[2\sqrt[4]{80}\] so you need to rewrite the radical as the product of factors \[2\sqrt[4]{80}= 2 \sqrt[4]{16 \times 5}\] which can be written as \[2 \times \sqrt[4]{16} \times \sqrt[4]{5}\] now you should be able to work from there

OpenStudy (iwanttogotostanford):

ok, I need a little guidance still on the last step... please

OpenStudy (iwanttogotostanford):

would I do 16 times 5? and then add the exponents

OpenStudy (iwanttogotostanford):

or would I distribute the 16 to 4 times 4 to get 8 on the outside?

OpenStudy (iwanttogotostanford):

@campbell_st ? still need help...

OpenStudy (campbell_st):

well you need to know \[16 = 2^4\] so now you should be able to simplify the problem

OpenStudy (iwanttogotostanford):

@zepdrix

OpenStudy (campbell_st):

so the problem becomes \[2\sqrt[4]{80} = 2 \times \sqrt[4]{2^4} \times \sqrt[4]{5}\] just simplify the 1st radical

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