Can you show me how to write an equation of an ellipse centered at the origin, satisfying the given conditions?

Question

anonymous · Answer

conditions:  
foci (+(underline) 2,0); co-vertices (0,+(underline)6) @DanJS

danjs · Answer

remember the standard form of an ellipse at the origin,  both terms are +

x^2/a^2 + y^2/b^2  = 1

anonymous · Answer

yes

danjs · Answer

so you just need to find the value for a and b

anonymous · Answer

how

danjs · Answer

|dw:1452137012394:dw|
that is what is given

danjs · Answer

b is that 6 distance to those vertices from the center (0,0)

danjs · Answer

|dw:1452137244186:dw|

the shape forms all the points where the sum of the distances to two fixed points (the foci) is constant

anonymous · Answer

b=6 from the center 0,0
a=?

anonymous · Answer

2?

danjs · Answer

yeah and the focii are 2 from the center

anonymous · Answer

can u put it all together

danjs · Answer

using that the distance from any point on the ellipse to both focii, sums to a constant value

you can play with right triangles in this case to find
|dw:1452138147921:dw|

anonymous · Answer

thanks
that it right or is there more to it

danjs · Answer

seems it for this prob

a = root(40), not much bigger than the minor axis of b=6, yeah that is it, just find 'a' and 'b' and they told you the center

anonymous · Answer

3 more

anonymous · Answer

???

danjs · Answer

yeah sure

danjs · Answer

sprry i been distracted