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Chemistry 13 Online
OpenStudy (a1234):

You have 22.1 grams of magnesium chloride. Find... 1. the number of moles of magnesium 2. the number of atoms of magnesium

OpenStudy (a1234):

Are they 0.232 moles and 1.3975 X 10^23 atoms?

OpenStudy (priyar):

No.of.moles=given wt./molecular wt no. of atoms=no. of. moles* 6.023*(10^23)

OpenStudy (a1234):

The molar mass is 95.211 g/mol. 22.1/95.211 = 0.232

OpenStudy (a1234):

Is that correct @priyar ?

OpenStudy (priyar):

yes..but what you have obtained is the no.of. moles of MgCl2

OpenStudy (priyar):

Luckily, In this case no. of. moles of MgCl2=no of moles of Mg since one mole of Mg is present in every one mole of Mgcl2....got it @a1234 ?

OpenStudy (a1234):

Yes...I thought so. Thanks

OpenStudy (priyar):

you are welcome!

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