Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (tiffany_rhodes):

I'm having trouble starting a proof. I'm supposed to prove that for every z in the set of complex numbers (excluding 0), there exists a w in the set of complex numbers, such that z*w =1. I'm supposed to use the fact that z=a+ib and z* = a-ib = a^2 + b^2. I know that I'm basically proving that there exists a multiplicative inverse for complex numbers. Sorry in advance for my formatting. I don't want help solving the entire proof, just getting started.

OpenStudy (anonymous):

do youknow what the multiplicative inverse of a complex number is?

OpenStudy (anonymous):

set \[(a+bi)(c+di)=1\] and solve for \(c, d\) in terms of \(a\) and \(b\)

OpenStudy (tiffany_rhodes):

Yes, a/(a^2 + b^2) - b/(a^2 + b^2) i @satellite73

OpenStudy (tiffany_rhodes):

Okay, I will try that. Thanks :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!