Question

can someone help me get he value of "X" just set up the equation @Natash18 @Lighthouseluver

Answer 1

@Natasha18

Answer 2

midpoint of a line is just the average of the end points. If you have a line going from \((3,5)\) to \((7,11)\), the midpoint will be at \[(\frac{3+7}2,\frac{5+11}2) = (5,8)\]

Answer 3

so how do i do my question

Answer 4

@whpalmer4

Answer 5

you need to find midpoint of line from point A to point C

the x coordinate will be the average of the x-coordinate of A and the x coordinate of C
the y coordinate will be the average of the y coordinate of A and the y coordinate of C

to find the average of two numbers, add them, then divide the sum by 2

Answer 6

A (0 ; 0) B (2 ; 2) C (5 ; - 1)


Midpoint of [AC]

xL = (xA + xC)/2 = (0 + 5)/2 = 5/2

yL = (yA + yC)/2 = (0 - 1)/2 = - 1/2

→ L (5/2 ; - 1/2)


Midpoint of [BC]

xM = (xB + xC)/2 = (2 + 5)/2 = 7/2

yM = (yB + yC)/2 = (2 - 1)/2 = 1/2

→ M (7/2 ; 1/2)


Equation of the line (LM)

The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept

To calculate m

m = (yM - yL) / (xM - xL)

m = [(1/2) - (- 1/2)] / [(7/2) - (5/2)]

m = [(1/2) + (1/2)] / [(2/2)]

m = 1 / 1

m = 1 ← this is the slope of the line (LM)


Equation of the line (AB)

The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept

To calculate m

m = (yB - yA) / (xB - xA)

m = (2 - 0) / (2 - 0)

m = 1 ← this is the slope of the line (AB)


→ Two lines are parallel if they have the same slope. It's the case for (LM) and (AB).


Distance LM

xLM = xM - xL = (7/2) - (5/2) = 2/2 = 1

yLM = yM - yL = (1/2) - (- 1/2) = (1/2) + (1/2) = 1

LM² = xLM² + yLM² = 1² + 1² = 2

LM = √2


Distance AB

xAB = xB - xA = 2 - 0 = 2

yAB = yB - yA = 2 - 0 = 2

AB² = xAB² + yAB² = 2² + 2² = 8

AB = √8

AB = 2√2



LM/AB = (√2) / (2√2)

LM/AB = 1/2

→ LM = (1/2).AB

Answer 7

I'm not really smart enough to figure that ^^ out lol my teacher helped me :D

Answer 8

well, you get a medal for all the typing, and getting your teacher to help you help someone else 😀

Answer 9

Well then, thank you :)

Answer 10

Did I help you? It was kind of confusing for me to understand lol

Answer 11

yes, you helped me by saving me the effort of explaining the rest of the problem. I can't speak for the person who posted the question, however...

Answer 12

@whpalmer4 I'm glad I could help :)