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Mathematics 15 Online
OpenStudy (stuck-help):

find the angle measurements help with # 18 then i will try to do the other 2

OpenStudy (stuck-help):

OpenStudy (stuck-help):

@Michele_Laino

OpenStudy (igigighjkl):

What grade is this.

OpenStudy (igigighjkl):

Do you want the awnser or no?

OpenStudy (michele_laino):

by definition of incenter, P is the intersection point of the bisectors, so we have: \[m\angle PXY = \frac{{90}}{2} = ...?\]

OpenStudy (stuck-help):

45

OpenStudy (igigighjkl):

The measurement is an acute angle.

OpenStudy (michele_laino):

that's right!

OpenStudy (igigighjkl):

Yes!

OpenStudy (stuck-help):

would 19 by 40

OpenStudy (igigighjkl):

?...What grade is this again.

OpenStudy (stuck-help):

its geometry

OpenStudy (igigighjkl):

No, grade.

OpenStudy (michele_laino):

yes! that's right! It is 40 degrees

OpenStudy (stuck-help):

10th grade but just because thats the grade i take it in does not mean that is the grade everyone takes it in and ok i will try 20 now

OpenStudy (igigighjkl):

an acute.

OpenStudy (michele_laino):

for question #20 we have: \[m\angle XZY = 180 - \left( {40 + 90} \right) = ...?\]

OpenStudy (igigighjkl):

???

OpenStudy (michele_laino):

hence: \[m\angle PZX = \frac{{m\angle XZY}}{2} = ...?\]

OpenStudy (stuck-help):

30

OpenStudy (igigighjkl):

?!?!?!

OpenStudy (stuck-help):

no hold on

OpenStudy (stuck-help):

its 50 not 30

OpenStudy (michele_laino):

so, what is: \[m\angle PZX = \frac{{m\angle XZY}}{2} = ...?\]

OpenStudy (stuck-help):

25

OpenStudy (michele_laino):

that's right!

OpenStudy (stuck-help):

thank you some much

OpenStudy (michele_laino):

:)

OpenStudy (igigighjkl):

?

OpenStudy (igigighjkl):

Bye.

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