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OpenStudy (stuck-help):
find the angle measurements help with # 18 then i will try to do the other 2
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OpenStudy (stuck-help):
OpenStudy (stuck-help):
@Michele_Laino
OpenStudy (igigighjkl):
What grade is this.
OpenStudy (igigighjkl):
Do you want the awnser or no?
OpenStudy (michele_laino):
by definition of incenter, P is the intersection point of the bisectors, so we have:
\[m\angle PXY = \frac{{90}}{2} = ...?\]
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OpenStudy (stuck-help):
45
OpenStudy (igigighjkl):
The measurement is an acute angle.
OpenStudy (michele_laino):
that's right!
OpenStudy (igigighjkl):
Yes!
OpenStudy (stuck-help):
would 19 by 40
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OpenStudy (igigighjkl):
?...What grade is this again.
OpenStudy (stuck-help):
its geometry
OpenStudy (igigighjkl):
No, grade.
OpenStudy (michele_laino):
yes! that's right! It is 40 degrees
OpenStudy (stuck-help):
10th grade but just because thats the grade i take it in does not mean that is the grade everyone takes it in and ok i will try 20 now
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OpenStudy (igigighjkl):
an acute.
OpenStudy (michele_laino):
for question #20
we have:
\[m\angle XZY = 180 - \left( {40 + 90} \right) = ...?\]
OpenStudy (igigighjkl):
???
OpenStudy (michele_laino):
hence:
\[m\angle PZX = \frac{{m\angle XZY}}{2} = ...?\]
OpenStudy (stuck-help):
30
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OpenStudy (igigighjkl):
?!?!?!
OpenStudy (stuck-help):
no hold on
OpenStudy (stuck-help):
its 50 not 30
OpenStudy (michele_laino):
so, what is:
\[m\angle PZX = \frac{{m\angle XZY}}{2} = ...?\]
OpenStudy (stuck-help):
25
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OpenStudy (michele_laino):
that's right!
OpenStudy (stuck-help):
thank you some much
OpenStudy (michele_laino):
:)
OpenStudy (igigighjkl):
?
OpenStudy (igigighjkl):
Bye.
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