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Mathematics 12 Online
OpenStudy (daisyduck04):

Find the distance between the points on the coordinate plane. points I and C A. –2 B. 2 C. 4 D. 5

OpenStudy (daisyduck04):

OpenStudy (daisyduck04):

@Mehek14 @LoveIt

OpenStudy (daisyduck04):

@Awolflover1

OpenStudy (daisyduck04):

can u help please

Awolflover1 (awolflover1):

Okay. Do you know where is Point C at?

OpenStudy (daisyduck04):

(-1,1)

Awolflover1 (awolflover1):

Correct, What about I?

OpenStudy (daisyduck04):

(4,1)

OpenStudy (anonymous):

Wait for c isn't it (1,-1)?

OpenStudy (daisyduck04):

no

Awolflover1 (awolflover1):

No..

OpenStudy (anonymous):

brb

Awolflover1 (awolflover1):

Okay, so count to C to I

OpenStudy (daisyduck04):

ok @Awolflover1

OpenStudy (daisyduck04):

@Awolflover1

OpenStudy (daisyduck04):

is it 5 ?

pooja195 (pooja195):

Can you tell me the coordinates of the 2 points first?

OpenStudy (daisyduck04):

ok (-1,1) for l and (4,1) for c

pooja195 (pooja195):

perfect have you ever heard of the distance formula it looks like this: \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

OpenStudy (daisyduck04):

that equation thing does not make sence

pooja195 (pooja195):

I'll teach it to you :P \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] We know our coordinates C comes before I so (4,1) <---coordinate 1 (-1,1) <---coordinate 2 Plug in the numbers. \[\huge d=\sqrt{(-1-4)^2+(1-1)^2}\] -1-4=?

OpenStudy (anonymous):

Pooja is it (x,y) or (y,x) because I always thought it was (x,y)

pooja195 (pooja195):

(x,y)

OpenStudy (anonymous):

So then for c should it be (1,-1)?

pooja195 (pooja195):

You're right! \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] We know our coordinates C comes before I so (4,1) <---coordinate 1 (1,-1) <---coordinate 2 Plug in the numbers. \[\huge d=\sqrt{(1-4)^2+(-1-1)^2}\] so...1-4=?

pooja195 (pooja195):

@daisyduck04

OpenStudy (anonymous):

That kind of goes for 1 too right? So (1,4)?

OpenStudy (anonymous):

I

pooja195 (pooja195):

We literally flipped the equation ,-, it wouldn't have mattered but ur correct \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] We know our coordinates C comes before I so (1,4) <---coordinate 1 (1,-1) <---coordinate 2 Plug in the numbers. \[\huge d=\sqrt{(1-1)^2+(-1-4)^2}\] \[\huge d=\sqrt{(0)^2+(-5)^2}\] 0^2=0 -5^2=25 \[\huge d=\sqrt{25}\] \[\huge d=5\]

pooja195 (pooja195):

You had it correct just showed u a different way of getting the answer :-)

OpenStudy (anonymous):

Oh sorry

pooja195 (pooja195):

Thanks @LoveIt <3 don't be sorry ;)

OpenStudy (daisyduck04):

@LoveIt @@pooja195 sorry internet problems

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