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Mathematics 14 Online
OpenStudy (blackstreet23):

Could somebody help me with this SAT question?

OpenStudy (blackstreet23):

OpenStudy (blackstreet23):

@DanJS

zepdrix (zepdrix):

Can we agree that this is a good starting point? \(\large\rm 2<x<10\) Understand that much of it? :)

OpenStudy (boldjon):

man this question's hard

OpenStudy (boldjon):

but here, i tried he problem says x represents the weight of a pumpkin he will NOT use, but he will use a pumpkin that weighs 2-10 lbs (including pumpkins that weigh 2 or 10 lbs). For this reason you can not substitute the numbers 2 and 10 in for x. D would still be the correct as written because if you put the number 1 in for x you get -5 and the absolute value of -5 is greater than 4. When you put in 11 for x you get 5 which is also greater than 4.

zepdrix (zepdrix):

It's not too bad :3 it's just a weird math trick.

OpenStudy (blackstreet23):

@freckles @Hero @jim_thompson5910 @pooja195

OpenStudy (blackstreet23):

I am soooo confused

OpenStudy (blackstreet23):

@SolomonZelman

OpenStudy (blackstreet23):

@Mehek14

OpenStudy (boldjon):

dude it's C cuz the problem says x represents the weight of a pumpkin he will NOT use, but he will use a pumpkin that weighs 2-10 lbs (including pumpkins that weigh 2 or 10 lbs). For this reason you can not substitute the numbers 2 and 10 in for x. D would still be the correct as written because if you put the number 1 in for x you get -5 and the absolute value of -5 is greater than 4. When you put in 11 for x you get 5 which is also greater than 4.

OpenStudy (danjs):

an absolute value inequality for a distance will result in 2 answers, this will be an OR statement, Uses Pumkins 2 to 10 lbs the values are an AND compound inequality for X doesnt use all others, less than 2 or greater than 10, an OR of two inequalities

OpenStudy (danjs):

looking for the function tha twill result in x<2 OR x>10 ,

OpenStudy (blackstreet23):

yes that part i get

OpenStudy (blackstreet23):

but how do i make that into one of those weird choices

zepdrix (zepdrix):

Oh x represents the weights he `will not use`. Oh I've been bamboozled 0_o interesting.

OpenStudy (danjs):

or covers all those intervals at least i think that is how it is worded

OpenStudy (danjs):

the absolute value quantity is a distance value, which is positive, look at the graph of absolute value x so it depends on if you are saying greater or less than on how you would want to solve it

zepdrix (zepdrix):

\(\large\rm |x-2|>10\) This can be rewritten as: \(\large\rm \pm(x-2)>10\) This will give you two equations. For the positive, \(\large\rm x-2>10\) gives us \(\large\rm x>12\). For the negative, \(\large\rm x-2<-10\), remember that multiplying a negative across an inequality flips the inequality sign. And that leads to \(\large\rm x<-8\). These numbers don't make sense, so not option A, ya?

zepdrix (zepdrix):

This is one approach at least. Working backwards from the solutions, trying to see which one gives you x<2 and x>10

zepdrix (zepdrix):

Yah this problem is harder than I thought it was going to be :) I hate the SAT lol. ACT is much nicer.

OpenStudy (blackstreet23):

Answer is D

OpenStudy (blackstreet23):

I dont understand why is that?

OpenStudy (danjs):

yeah absolute value is a distance, to be greater than something, the direction doesnt matter if you move + or - direction like starting at zzero, and saying | x | > 5, the greater than results in an OR solution |dw:1452219009373:dw|

OpenStudy (danjs):

if it were |x| < 5 , instead, that limits it to less than 5 in either direction, so the solution there would be -5 <x <5, a compound AND inequality

OpenStudy (danjs):

you want the one that will give you the less than 2 and bigger than 10 values, although 0 or negative values for a weight is not real, but it just wants the answer that will cover it i guess

OpenStudy (blackstreet23):

@freckles @ganeshie8

OpenStudy (mathmale):

Pumpkin is to weigh no less than 2 lb and no more than 10 lb? Graph that on a number line. Can you finish the following graph by labeling it?|dw:1452221012798:dw|

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