Could somebody help me with this SAT question?
@DanJS
Can we agree that this is a good starting point? \(\large\rm 2<x<10\) Understand that much of it? :)
man this question's hard
but here, i tried he problem says x represents the weight of a pumpkin he will NOT use, but he will use a pumpkin that weighs 2-10 lbs (including pumpkins that weigh 2 or 10 lbs). For this reason you can not substitute the numbers 2 and 10 in for x. D would still be the correct as written because if you put the number 1 in for x you get -5 and the absolute value of -5 is greater than 4. When you put in 11 for x you get 5 which is also greater than 4.
It's not too bad :3 it's just a weird math trick.
@freckles @Hero @jim_thompson5910 @pooja195
I am soooo confused
@SolomonZelman
@Mehek14
dude it's C cuz the problem says x represents the weight of a pumpkin he will NOT use, but he will use a pumpkin that weighs 2-10 lbs (including pumpkins that weigh 2 or 10 lbs). For this reason you can not substitute the numbers 2 and 10 in for x. D would still be the correct as written because if you put the number 1 in for x you get -5 and the absolute value of -5 is greater than 4. When you put in 11 for x you get 5 which is also greater than 4.
an absolute value inequality for a distance will result in 2 answers, this will be an OR statement, Uses Pumkins 2 to 10 lbs the values are an AND compound inequality for X doesnt use all others, less than 2 or greater than 10, an OR of two inequalities
looking for the function tha twill result in x<2 OR x>10 ,
yes that part i get
but how do i make that into one of those weird choices
Oh x represents the weights he `will not use`. Oh I've been bamboozled 0_o interesting.
or covers all those intervals at least i think that is how it is worded
the absolute value quantity is a distance value, which is positive, look at the graph of absolute value x so it depends on if you are saying greater or less than on how you would want to solve it
\(\large\rm |x-2|>10\) This can be rewritten as: \(\large\rm \pm(x-2)>10\) This will give you two equations. For the positive, \(\large\rm x-2>10\) gives us \(\large\rm x>12\). For the negative, \(\large\rm x-2<-10\), remember that multiplying a negative across an inequality flips the inequality sign. And that leads to \(\large\rm x<-8\). These numbers don't make sense, so not option A, ya?
This is one approach at least. Working backwards from the solutions, trying to see which one gives you x<2 and x>10
Yah this problem is harder than I thought it was going to be :) I hate the SAT lol. ACT is much nicer.
Answer is D
I dont understand why is that?
yeah absolute value is a distance, to be greater than something, the direction doesnt matter if you move + or - direction like starting at zzero, and saying | x | > 5, the greater than results in an OR solution |dw:1452219009373:dw|
if it were |x| < 5 , instead, that limits it to less than 5 in either direction, so the solution there would be -5 <x <5, a compound AND inequality
you want the one that will give you the less than 2 and bigger than 10 values, although 0 or negative values for a weight is not real, but it just wants the answer that will cover it i guess
@freckles @ganeshie8
Pumpkin is to weigh no less than 2 lb and no more than 10 lb? Graph that on a number line. Can you finish the following graph by labeling it?|dw:1452221012798:dw|
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