Question

Someone please check my answer
Consider this function:
f(x)=(x^2-9)(4x^2+4x-3)
What are the zeros of the function?
A)-3, -2/3, 2, 3
B)-3, -2/3, -2, 3
C)-3, -3/2, 1/2, 3
D)-3, -1/2, 3/2, 3
i believe is is C but i dont think its right... very confused please help will give medals!!

Answer 1

To find the zeros, or roots, of the function you replace f(x) with 0 and solve for x


f(x)=(x^2-9)(4x^2+4x-3)
0=(x^2-9)(4x^2+4x-3)
(x^2-9)(4x^2+4x-3) = 0
x^2-9 = 0 or 4x^2+4x-3 = 0


From here you have to solve x^2-9 = 0 and you also have to solve 4x^2+4x-3 = 0

You can use the quadratic formula for each

Answer 2

Hmmmmm..... I do not know about this one... i will do a bit of researching and get back to you maybe @jim_thompson5910 can help?

Answer 3

how would I use the quadratic equation when there isn't an a b and c?? I'm sorry if I sound stupid

Answer 4

x^2-9 = 0 is the same as 1x^2+0x+(-9) = 0

so here

a = 1
b = 0
c = -9

Answer 5

oh yea thats right. so if i use the quadratic equation i will get the answer?