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Mathematics 16 Online
OpenStudy (rootbeer003):

please help

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

heres the first one that idk

OpenStudy (anonymous):

3rd one

OpenStudy (anonymous):

this one is way way easier tha the others

OpenStudy (mehek.15):

you can't have same x values but different y values

OpenStudy (anonymous):

pick the one that has no repeats in the first (the \(x\)) coordinate

OpenStudy (rootbeer003):

a?

OpenStudy (anonymous):

in other words, ignore the second coordinates entirely, just look at the first one ans make sure they are all different

OpenStudy (rootbeer003):

oo

OpenStudy (rootbeer003):

c

OpenStudy (mehek.15):

@Rootbeer003 In A, 2 is repeated for x so it can't be A

OpenStudy (mehek.15):

ye C

OpenStudy (anonymous):

A has a repeated 2 in the first spot, so not -that one

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

am i right

OpenStudy (anonymous):

no

OpenStudy (rootbeer003):

oh 14

OpenStudy (rootbeer003):

did it wrong

OpenStudy (anonymous):

\[f(x)=2-3x\\ f(-4)=2-3\times (-4)\]

OpenStudy (anonymous):

yeah 14

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

idk this

OpenStudy (rootbeer003):

b?

OpenStudy (anonymous):

they are asking for the value of \(x\) for which \(x+4=0\)

OpenStudy (anonymous):

so no, not B

OpenStudy (rootbeer003):

a?

OpenStudy (anonymous):

lol now you are guessing i am sure you can solve \[x+4=0\] for \(x\) right?

OpenStudy (rootbeer003):

is its a

OpenStudy (rootbeer003):

so*

OpenStudy (anonymous):

no, A is \((0,4)\)

OpenStudy (anonymous):

what is \(x\) if \(x+4=0\)?

OpenStudy (rootbeer003):

so b

OpenStudy (rootbeer003):

lol im so dumb

OpenStudy (rootbeer003):

its so b

OpenStudy (anonymous):

no, you are just guessing don't guess solve \[x+4=0\] for \(x\) if it is not clear how to do it, just say so forget about abcd for a second

OpenStudy (rootbeer003):

lol k

OpenStudy (rootbeer003):

idk

OpenStudy (anonymous):

did you solve \[x+4=0\] yet?

OpenStudy (rootbeer003):

its 4

OpenStudy (anonymous):

no \(4+4=8\) not zero

OpenStudy (rootbeer003):

0

OpenStudy (rootbeer003):

-4

OpenStudy (rootbeer003):

OHHH WOOOW

OpenStudy (anonymous):

i don't mean to torture you lets solve it ok? if \(x+4=0\) then if you subtract \(4\) from both sides you get \(x=-4\) whew you got it!

OpenStudy (rootbeer003):

so c

OpenStudy (anonymous):

so if \(x=-4\) then you have \(|-4+4|=0\) the point is \((-4,0)\)

OpenStudy (anonymous):

yeah C

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

the secound one says d so

OpenStudy (rootbeer003):

i was thinking the last one?

OpenStudy (anonymous):

ok once again lets solve\[x-3=0\]for \(x\)

OpenStudy (rootbeer003):

-3

OpenStudy (anonymous):

lol no

OpenStudy (anonymous):

\[-3-3=-6\] not zero

OpenStudy (rootbeer003):

3

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that means the point \((3,0)\) is the lowest point on the V shaped graph

OpenStudy (rootbeer003):

so its on the positive side

OpenStudy (anonymous):

it looks like this http://www.wolframalpha.com/input/?i= |x-3|

OpenStudy (anonymous):

ah you have to copy and past that

OpenStudy (anonymous):

yes, on the positive side

OpenStudy (rootbeer003):

a?

OpenStudy (anonymous):

ok go ahead pick from abcd

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

yay

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

am i right

OpenStudy (anonymous):

yay?

OpenStudy (rootbeer003):

i meant on the one before

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

oh ok site is lagging for me

OpenStudy (rootbeer003):

im right on that one?

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

well it says im typing when im not so

OpenStudy (anonymous):

the last one is not right

OpenStudy (anonymous):

\[-6\times -4=24\] so you need \[-6\times 12\]

OpenStudy (rootbeer003):

i still dont know

OpenStudy (anonymous):

what is \(-6\times 12\)?

OpenStudy (rootbeer003):

oh are you talking about the one i chose -2 on?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

-2 is wrong

OpenStudy (rootbeer003):

-72

OpenStudy (anonymous):

you divided,,you should multiply -72 is right

OpenStudy (rootbeer003):

oh ok

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

how bout dis

OpenStudy (anonymous):

how the hell are you supposed to know this?

OpenStudy (rootbeer003):

what?

OpenStudy (anonymous):

i have no idea how you are supposed to know this , but the second one down the one with (2,1), (3,4) , (4,9) ,(5,16) is the same as \[y=(x-1)^2\]

OpenStudy (anonymous):

i think that is what they mean by "quadratic variation" is is certainly not the last two

OpenStudy (rootbeer003):

huh so b

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