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OpenStudy (blackstreet23):
2 (x^22+b24)
OpenStudy (blackstreet23):
sorry
OpenStudy (blackstreet23):
2 (x^22 + 24)
OpenStudy (mathmale):
This expression has two terms. Blackstreet23 has recognized that the factor 2 was common to both terms, so he factored that out. @arbyj: Is any further factoring possible?
OpenStudy (arbyj):
uhh no
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OpenStudy (arbyj):
so it would just be 2(x^2+11x+24)?
OpenStudy (blackstreet23):
ohh it has more elements.
OpenStudy (arbyj):
oh snap i set it up wrong i apologize haha
OpenStudy (blackstreet23):
can you show me the original?
OpenStudy (arbyj):
i edited my question
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OpenStudy (anonymous):
still factor out a 2
OpenStudy (blackstreet23):
you need to apply the quadratic formula.
OpenStudy (anonymous):
he's trying to factor it though not solve it
OpenStudy (anonymous):
what are two factors of 24 that sum to 11?
OpenStudy (blackstreet23):
\[(-b + - \sqrt{b^2-4ac})/2\]
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OpenStudy (arbyj):
8 & 3
OpenStudy (anonymous):
so your answer is 2(x+8)(x+3)
OpenStudy (arbyj):
ohh kay
OpenStudy (blackstreet23):
ohh yeah he is right
OpenStudy (arbyj):
so i was supposed to divide everything by 2?
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OpenStudy (anonymous):
Factoring out the 2 makes it easier to factor. (Keep in mind you aren't dividing it by 2 you are just factoring out a 2. The 2 is still there.)
OpenStudy (arbyj):
ohh okay
OpenStudy (anonymous):
An example of this could be 5x^2+65x+180 you would factor out a 5 took make the whole expression much easier to factor.