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Mathematics 14 Online
OpenStudy (howard-wolowitz):

I do NOT understand how to do this type of problem, but would like to so I need some assistance.

OpenStudy (howard-wolowitz):

The average time it takes a lawn to be mowed is 1.35 hours with a standard deviation of 0.25. What is the z-score of a lawn that takes 2.15 hours to mow? A. 0.71 B. 2.49 C. 2.7 D. 3.2

OpenStudy (howard-wolowitz):

show me how to do this tep by step please

OpenStudy (howard-wolowitz):

@tkhunny I need to see some light

OpenStudy (anonymous):

Hi ill help

OpenStudy (howard-wolowitz):

Thank you!

OpenStudy (anonymous):

The answer is B, your welcome, bye

OpenStudy (howard-wolowitz):

bu how do you do thisssssss

OpenStudy (tkhunny):

Just calculate the z-score. \(\dfrac{2.15 - 1.35}{0.25}\) This should nto be challenging you. Memorize the calculation. Get it in your head.

OpenStudy (anonymous):

Exactly.

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