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OpenStudy (anonymous):
OpenStudy (anonymous):
@Michele_Laino
OpenStudy (zenmo):
you can do this by visually looking at the graph
OpenStudy (michele_laino):
hint:
such line passes at point \((1,-2)\)
OpenStudy (michele_laino):
so, such coordinates have to check the requested equation.
For example, if I replace \(x=1\) into the first equation, I get:
\(f(1)=(-1/3) \cdot 1+1=2/3\) which is different from \(-2\)
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OpenStudy (michele_laino):
so, the first option, is a wrong option
OpenStudy (anonymous):
Oh...
OpenStudy (michele_laino):
so, what is the right option?
OpenStudy (anonymous):
I am thinking :3
OpenStudy (anonymous):
The third option..?
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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (michele_laino):
third option is a wrong option, since if I replace x=1, I get:
f(1)=3 *1+1=3+1=4, which is different from -2
OpenStudy (anonymous):
Ohhhhh
OpenStudy (anonymous):
Makes sense. Then I will have to go with the second one know because I am pretty sure the final one is incorrect.
OpenStudy (michele_laino):
I think that the last option is the correct option
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OpenStudy (anonymous):
Ihml xD
OpenStudy (michele_laino):
hint:
if I replace x=1, I get:
\(f(1)=-3x+1=-3 \cdot (1)+1=-3+1=-2\)