For the unbalanced equation

NH3 + O2 → NO + H2O

If at the beginning of the reaction you used 4.30 g NH3 and 15.76 g O2, what is the theoretical yield (in grams) of H2O (you will need to find the limiting reagent and then the theoretical yield of H2O from this reagent)?

Question

For the unbalanced equation

NH3 + O2 → NO + H2O

If at the beginning of the reaction you used 4.30 g NH3 and 15.76 g O2, what is the theoretical yield (in grams) of H2O (you will need to find the limiting reagent and then the theoretical yield of H2O from this reagent)?

photon336 · Answer

You need to balance the equation first before doing anything else

anonymous · Answer

what Do I have to do after I Have balanced the equation??

photon336 · Answer

Calculate the molar mass of NH3 O2 and H2O

Could you show me what you have so far?

anonymous · Answer

NH3 - 4.30g X 4 mol/17.03g = 1.009982384 mols

anonymous · Answer

02 - 15.76g* 5 mol/32g = 2.4625

h20- 6 mol * 18.02/1 mol = 108.12 g