Neil has been running a tutoring business since 2005. He charges a monthly fee for weekly tutoring sessions and a phone help line. Each year, he has increased his fee by the same amount. The table shows what Neil charged each customer for two given years of his business: Year Annual Tutoring Fee 2005 $1200 2008 $1350 A. What is the rate of change and initial value for Neil's business? How do you know? B. Write an equation in slope-intercept form to represent the fees that Neil charges each year.
ello
hey
mate For the chart it's 1200 and 1350 for the prices and 2005 and 2008 for the years
Find the slope from the two given points: (0,1200) and (3,1350) \text{Slope } = \frac{ y_2 - y_1 } { x_2 - x_1 }= \frac{ 1350 - 1200}{ 3 - 0} = \frac{ 150}{ 3} =\boxed{\bf{ 50}} y = 50x + b Plug in the point: (0,1200) 1200 = 50(0) + b 1200 = b b = 1200 y = 50x + 1200 Part A. The rate of change is 50. The initial value is 1200. Part B. The equation in slope-intercept form is y = 50x + 1200.
the points 0 and 3, instead of 2005 and 2008, because 2005 was the first year he started his business. And therefore, 2008 was the 3rd year his business was running.
wow that was fast
Thankkssss.
u understand
ANY OTHER QUESTIONS MATEE
thats it for now it was just this one
Here mite not see right but
:3
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