Can someone please help me with this?! Will medal!
Quadrilateral ABCD in the figure below represents a scaled-down model of a walkway around a historic site. Quadrilateral EFGH represents the actual walkway. ABCD is similar to EFGH. What is the total length, in feet, of the actual walkway? Numerical Answers Expected!
It's a scale model. All parts are proportional.
ok yes I know that. @tkhunny
@tkhunny can you come and help me?
@mathmale help please
Well, why don't you calculate the proportional parts? You have 6":72' There's your proportion.
then what? @tkhunny
Use that proportion to calculate the lengths of the other sides.
can you help me with that?! I am not very good at geometry.
a corresponding larger side will be 6/72 times the smaller side
to move from small shape to the similar larger one, that is the scale
tjhunny has shared the following with you already: You have 6":72' There's your proportion. that is, 6 inches on the model or drawing represents 72 feet in real life. You can make up a unit conversion factor, either\[\frac{ 6inches }{ 72feet }\]
Careful, that's 6 inches to 72 feet. That's quite a bit bigger than 6/72.
or the reciprocal of that. Now, if you want to find the length of side FG, look at the model to see how long the corresponding side is. You figure out: should you multiply that length (3 inches) by the appropriate form of the conversion factor to get the "real life" length in feet.
What is the length of the model's side BC, in inches? Kitty: this question's for you.
ah i see that now i would use 1/2, 1/4, 1/4, 1/3 feet for the small lengths, so half a foot is to 72 feet as 1/4 foot is to FG
what is the total length, in feet, of the actual walkway?
is 1/4 the answer? I am a little confused.
To answer my own question: Side BC is 3 inches long. We want to convert this measurement to feet in the real-life situation. Multiplying 3 inches by \[\frac{ 72ft }{ 6 inches}\] results in \[\frac{ 72feet }{ 6inches }(3inches)=36 feet.\]
Granted, there are other forms of the conversion factors, that involve inches to inches, feet to feet, and so on.
so 36 is the final answer?!
Kitty, I've re-read the problem. I don't think you need to find the area of the walkway, but rather you need to find the "length," however that is defined. (I find this part of the problem to be vague.)
you can set up equal proportions and solve for each side too like this \[\frac{ 1/2 }{ 72 } = \frac{ 1/4 }{ FG }\] solve , FG = 36
1/ 2 ft goes to 72 ft , as, 1/4 goes to FG,
the question is What is the total length, in feet, of the actual walkway?
same for the other sides to find
the total of all the sides, the perimeter
is 36 the answer?
I am confused
FG is 36 ft, GH is the same as tha tone 36ft also and 1/2 to 72 is the same as 1/3 to HE \[\frac{ 1/2 }{ 72 } = \frac{ 1/3 }{ HE }\] HE = 48 ft
total length is sum of the sides, 72 + 36 + 36 + 48 ft
equals 192
correct?! want to make sure!
the perimeters of both should still retain that same similarity ratio, the sum of linear factors, is still linear
4/3 ft goes to 192 ft same as 1/2 ft goes to 72
192 feet is the answer right? I have a lot of other questions to do and don't have all night.
yes or no please tell me!!
@DanJS @mathmale is the answer 192?!
Kitty, I'm sorry you're operating under pressure. Nevertheless, begging others to check your answers for you is NOT going to help you in the long run. What really counts is your ability to undrstand and apply the material (conversion factors and scale models) that you're learning here. Personally I'd be glad to confirm the correctness of your work IF and only IF you share it with me, so that I know how you obtained your answer.
Is there any way in which you could post questions and problems a bit earlier, so that you wouldn't have deadlines to worry about so much? Are your practice problems timed, or can you take a while to understand the problems in more depth?
i said --total length is sum of the sides, 72 + 36 + 36 + 48 ft you unsure calling that 192?
that was your work ,so idk
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