Question

http://prntscr.com/9nsfof

Answer 1

The two equations are:
x = 4y - 6
x - 3y = 4
Since we have the first equation solved for x, we can plug that into the second equation.
(4y - 6) -3y = 4 Now that we only have y's we can solve for y.
4y - 3y - 6 = 4
y - 6 = 4
y = 10 Now that we have y = 10 we can plug that back into the first equation.

x = 4(10) - 6
x = 40 - 6
x = 34

The two solutions are x = 34 and y = 10

Answer 2

So the answer is "(34, 10)"

Answer 3

Yep :)

Answer 4

Thanks! Can you help me with 3 more?

Answer 5

Sure, fire away

Answer 6

That was wrong @ttawney

Answer 7

http://prntscr.com/9nshzx

Answer 8

You made a mistake when plugging in 4y+6 for x. You plugged in 4y-6 which got you a wrong end result.

Answer 9

Always make sure to check your work

Answer 10

So the answer isn't (34, 10)?

Answer 11

It wasn't. But the method @ttawney presented was correct, so why not try solving it yourself? (:

Answer 12

Good catch...
The two equations are:
x = 4y + 6
x - 3y = 4
Since we have the first equation solved for x, we can plug that into the second equation.
(4y + 6) -3y = 4 Now that we only have y's we can solve for y.
4y - 3y + 6 = 4
y + 6 = 4
y = -2 Now that we have y = -2 we can plug that back into the first equation.

x = 4(-2) - 6
x = - 8 - 6
x = -14

The two solutions are x = -14 and y = -2

Answer 13

Okay, thanks! :)

Now what about this one? http://prntscr.com/9nsj64

Answer 14

@ttawney

Answer 15

You did the same thing @ttawney although this time it was when solving for x. It would be \[\large \sf x=4(-2)+6\]\[\large \sf x=-8+6\]\[\large \sf x=-2\]

Answer 16

So (-2, -14)?

Answer 17

@TheOutSmarter have you attempted solving the first one yourself? Is that how you are getting that answer?