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Mathematics 11 Online
OpenStudy (anonymous):

Can anyone explain how to solve 'consecutive integer problems' ?

imqwerty (imqwerty):

okay i'll tell here better Right. The sum of three consecutive integers is 75. Find the largest integer.

OpenStudy (qwertty123):

http://www.algebra.com/algebra/homework/word/numbers/Consecutive-Number-Word-Problems.lesson Here try this... Though it looks like @imqwerty is helping you just fine! :)

imqwerty (imqwerty):

so we have 3 integers which are consecutive remember that consecutive integers are like this-> \(\color{red}a\) , \(\color{red}{a}+1\) , \(\color{red}{a}+2\) and any two consecutive integers differ by 1

imqwerty (imqwerty):

okay till here?

OpenStudy (anonymous):

Yeah. Good so far

imqwerty (imqwerty):

okay so we are given that the sum of 3 consecutive integers is 75 so 1st we write 3 consecutive integers - \(a\) , \(a+1\), \(a+2\) and they u know that the sum of all these^ is 75 now try to make an equation from this information

OpenStudy (anonymous):

Wait, I dont quite know how to go about making it into an equation...

imqwerty (imqwerty):

okay 1st of all-> is it clear that we are assuming the consecutive numbers to be-> \(a\), \(a+1\) and \(a+2\) ?

OpenStudy (anonymous):

Yer. Is that with all them though? I mean, like if you had to find the sum of two it'd be x, x+1?

imqwerty (imqwerty):

yes :)

imqwerty (imqwerty):

okay so the sum of our 3 consecutive numbers \(x\), \(x+1\) and \(x+2\) will be this-> \(\large (x) + (x+1) +(x+2)\) okay?

OpenStudy (anonymous):

Right, got it so far. Next you group like terms?

imqwerty (imqwerty):

yes :) try to group like terms and simplify

OpenStudy (anonymous):

3a+3=75 Am I doing it so far? Or have I grouped wrong.

OpenStudy (anonymous):

Yer, now Im lost! 2+1=3... right?

imqwerty (imqwerty):

oh sorry :/ u did that correct

OpenStudy (qwertty123):

:)

imqwerty (imqwerty):

so we have our equation- \(\large 3a+3=75\) try to find \(a\) from here :)

OpenStudy (anonymous):

Haha, Its fine. So, I got a=24... ?

imqwerty (imqwerty):

yes correct :) \(a\) was our 1st term and we have it now the other terms we have to find are-> \(x+1\) and \(x+2\)

OpenStudy (anonymous):

There's more? haha So what are the other two variables for? I know what a was for, but not sure what this step is for.

imqwerty (imqwerty):

aww i made a type ;-; just replace that \(x\) with \(a\)

imqwerty (imqwerty):

*typo

OpenStudy (anonymous):

Another typo when saying you made a typo. ;) Lol So how do I find the other terms??

imqwerty (imqwerty):

a was our 1st term and we have it now the other terms we have to find are-> \(a+1\) and \(a+2 \) now know what \(a\) is just put its value in \(a+1\) and \(a+2\) to get these terms

OpenStudy (anonymous):

Oh!! Right. So 24+1 and 24+2?

imqwerty (imqwerty):

yes (B

OpenStudy (anonymous):

Okay... Uhm, not sure if im doing it right! My work so far; (24+1)+(24+2) 25 + 26 = 75 51 = 75 ? XD

imqwerty (imqwerty):

no no the question says-> The sum of three consecutive integers is 75. \(\color{red} {Find~ the~ largest ~integer~.}\) now we had these integers-> \(a\) , \(a+1\) and \(a+2\) tell me which one is largest

OpenStudy (anonymous):

2?

imqwerty (imqwerty):

wym by 2? :) do you mean the 2nd one? this-> \(a+1\) ?

OpenStudy (anonymous):

Oh, no I suppose I mean a+2

imqwerty (imqwerty):

yes correct :) now we had to find the largest integer and we know that it is this-> \(a+2\) we also know what is \(a\) so can you find \(a+2\) ?

OpenStudy (anonymous):

26?

imqwerty (imqwerty):

yes :) question=solved

OpenStudy (anonymous):

More than I thought It'd be haha Thank you so much though, I actually understand it now thanks to you ;)

imqwerty (imqwerty):

np :)

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