Question

Basic math help

Answer 1

Answer is 5.564x10^14

Answer 2

solving for Vo

Answer 3

2.935x10^-19=(hc/300x10^-9)-hVo

Where you are solving for Vo and h=6.626x10^-34 and c=3x10^8

Answer 4

It's physics by the way , and I know h is The Planck constant , c is speed light

2.935 * 10^-19 = h ( [ 3*10^8/300*10^-9) - Vo )

Vo = 2.935 * 10^-19 /h - 3*10^8/300*10^-9 * -1

Answer 5

You are right. This is for pchem :)

Answer 6

\[2.935 * 10^{-19} = \frac{ hc }{ 300 * 10^-9 } - hV_{o}\]

\[\frac{ 2.935 * 10^{-19} - \frac{ 6.626 * 10^{-34} * 3 * 10^8 }{ 300 * 10^{-9} } }{ -6.626*10^{-34} }\]

Answer 7

That is correct! Thank you! I understand everything you did, except why is top part negative? I see why the bottom is?

Answer 8

Nevermind, you moved it all over.

Answer 9

2.935x10^-19= (hc/300x10^-9) < this to the other side. -hVo

Answer 10

thanks so much!!!

Answer 11

Any time.