Write an equation for the translation of x^2+y^2=25 by 7 units left and 2 units down. (x+7)^2+(y+2)^2=25 (x-7)^2+(y+2)^2=25 (x+7)^2+(y-2)^2=25 (x-7)^2+(y-2)^2=25
@TheSmartOne
@Luigi0210
Okayy, so we have the equation of \(\Large x^2+y^2=25\) correct? Do you know what the center of this equation is?
No I don't. Will you help me?
Actually is the center just (0,0)? Because that is the center of the equation.
In order to under it, you'll need to know the basics of the conic shapes. And yes, the center would be (0,0) with a radius of 5. Now, we want to move it 7 units to the left, and 2 units down, like so: |dw:1452373139414:dw| (pretend that circle is the center) When we do that, we are moving in the x-direction (positively) and y-direction (negatively).. which in a coordinate point is (7, -3) The radius won't change though So change the (0, 0) to (7, -3) in \(\Large (x-0)^2+(y-0)^2=25 \)
*(7, -2) not (7, -3) my mistake
So C would be correct?
In short, \(\Large (\color{red}{7}, \color{blue}{-2}) \) will be the new \(\Large (\color{red}{h}, \color{blue}{k})\) And nope, try again: \(\Large (x-\color{red}{h})^2 +(y-\color{blue}{k}) =25 \) \(\Large (x-\color{red}{7})^2 +(y-\color{blue}{(-2)}) =25 \) Do understand it some at least?
Forgot the squares, but you get the point right?
So the opposite. -7 +2?
Yup! Gotta watch out for those negatives.
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