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Mathematics 19 Online
OpenStudy (anonymous):

If f'(x) = ln(x-2), then the graph of y = f(x) is decreasing if and only if a) 2< x < 3 b) 0 1 e) x > 2

OpenStudy (roadjester):

If the first derivative of a function is equal to 0, what can you discern from that?

OpenStudy (anonymous):

x = 2 ?

OpenStudy (roadjester):

Let's try this differently, ok, so do you know what the graph of \[ ln(x)\] looks like?

OpenStudy (anonymous):

yes |dw:1452372946319:dw|

OpenStudy (roadjester):

Good! Okay so ln(x-2) is simply shifted 2 units to the right. And Trojan, that is incorrect.

OpenStudy (anonymous):

|dw:1452373034309:dw|

OpenStudy (roadjester):

Therefore, do you agree that the asymptote of f'(x) is at x=2 and has a zero at x=3?

OpenStudy (anonymous):

i know that the slope is positive from that function

OpenStudy (roadjester):

f'(x)=0 at x=3 so that is where f(x) will change.

OpenStudy (roadjester):

Trojan, substitute 2.5, would you?

OpenStudy (roadjester):

|dw:1452373306066:dw|

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