How do I write the linear equation in slope - intercept form with slope=2/3 and y- intercept =-1
Do you know what slope intercept form is?
Yea
Can you type it out? Because after that, we will plug the slope in for m and the y intercept for b.
Slope= 2\3 yintercept= -1
That's what each of those values equal but not the actual form of the equation we're looking form. Can you try again?
Its slope- intercept Y= MX +B
True. But... we were asking you for the EQUATION of a strai8ght line in slope-intercept form. Point slope form is y-y1 = m (x - x1). This is not what we wanted, but it does illustrate one form of the equation of a line. Slope-intercept form? You research this... type out the proper form Essential that you know this form of the equation of a straight line.
So now that you know that, you can plug in the slope (2/3) for the m value. Then plug in the y intercept (-1) for the B.
So it would be y= 2\3 -1
Yes! Good job! That is the correct answer!
Thank you
So what about 2x+8y=16
Well, with an 'x' in there, anyway.
Jus solve it for y. Show your best algebra skills.
@tkhunny Yes that too. So for solve for y, and then once you do that, the equation will end up in slope intercept form
Would I subtract the 8y from 2y
When? Can you post the steps you are going through?
Yes 2x+8y=16
That's all I got
So first you would subtract 2x from both sides.
2x-8x=16 -2x. -2x
Let's keep track of the "8y", shall we?
2x-2x is zero. That leaves you with -8y on the left side. On the right side you'll have 16-2x. Write out this new form of the equation. Then, consider how you'd solve for y.
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