Find the x-, y, and z-intercepts for the equation. 2x - 6y - 3z = 12
What do you think the answer is? What have you tried so far?
(6, -2, -4) This... But it wasn't right... I don't think I'm doing it right.
So you need to figure out when x and y are 0, then what is x. As a first step
Is it 6?
No, try again. -3z=12
This, my friends, is why we acquaint ourselves with the "Intercept Form". 2x - 6y - 3z = 12 Divide by 12 \(\dfrac{x}{6}+\dfrac{y}{-2}+\dfrac{z}{-4} = 1\) Done. The three intercepts are now staring at you.
(6, -2, -4) I had the answer right originally I guess. Just was putting parenthesis... The answer was actually right.
Do NOT forget the intercept form.
Huh? o__o
Find the x-, y-, and z-intercepts for the equation. Enter your answers separated by commas; example: -2, 3.5, 4 3x – 5y + 10z = 15 I have another. How would I do this in intercept form??
Maybe divide by 15 and make sure all the operations are "+"? Go forth!! Divide!
3x, 5y, and 10z? I divide them all by 15 right?
0.2, 0.3, 0.6 ? O_o
...and make sure there is only addition. Look at my previous example. I had to alter some subtraction.
Erm... I don't get it I am sorry
Let's see your division.
I used a calculator to divide the numbers by 15 and got those 0. numbers above
Why would you use a calculator? That's just silly. Do the arithmetic. Are you allergic to fractions?
it's okay I am going to skip it for now and come back to it on Monday when my teacher is available D: I'm more of a visual learner, I don't understand math very well. Sorry if I sound like an idiot... I can't even divide in my head, and yeah... Fractions confuse the heck out of me..
Oh, come on! Really? Not even going to try it? Oh, well. Don't forget to mention the "Intercept Form" to your teacher.
LOL I did try... I just don't want to be made to feel stupid if I don't know how to do something
I will mention it. Thank you for helping me.
No "make you feel stupid" going on around here. Are you sure? Gotta' get up to speed on the fractions. They are NOT your enemy. Honest. :-)
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