Are any of these one-to-one functions? let f:{a,b,c,d}→{a,b,c,d} be given by 1. f(a)=b f(b)=a f(c)=c f(d)=d 2. f(a)=b f(b)=b f(c)=d f(d)=c 3. f(a)=d f(b)=b f(c)=c f(d)=d Is this next function onto?: Let f:{a,b,c,d}→{a,b,c,d}f:{a,b,c,d}→{a,b,c,d} be given by 4. f(a)=bf(a)=b f(b)=af(b)=a f(c)=cf(c)=c f(d)=df(d)=d
Start with the definition of a one-to-one function. Do you know what it is, and what the requirements are?
every x has a unique value so like (a,c)
That's the requirement for a function (it passes the vertical line test). If it's a 1-1 function, it also has to pass the horizontal line test - no y values are repeated either. So, for example #3 has d on there twice - once for f(a) and once for f(d). Therefore, it is not a 1-1 function.
the same for 2
Correct. what about 1?
i dont think so i keep getting something like a parabola
@wilsondanielle
i gave A - D values and graphed them a = 1 b = 2 c=3 d=4
I would argue that it would be, as you don't know the values of any of them and neither of them repeat.
what about number 4? f(a)=b f(b)=a f(c)=c f(d)=d the onto means every y value was used.
so i would say number 4 is onto @wilsondanielle
I believe so, because again neither x nor y values repeat.
ok, thank you
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