How do I solve for x in the equation y=-x+4?
Ok so you said y-4=x
No, y-4 = -x
^right divide everything by -1 what are you left with?
y+4 = x so x= y+4 right ?
Well the y was orginally positive so y/-1= ?
I have to do substitution The page says to solve each system by substitution The problem is y=-x+4 and then y=3x
I have to solve for x and then substitute it into the other equation.
ooohhh that makes sense y=-x+4 <---equation 1 y=3x <---equation 2 We know the value of y take equation 1 and plug it into equation 2 \[\huge~\rm~\bf~\color{blue}{ x+4}=3x\] Solve for x
Are you stuck?
Start by subtracting x from both sides \[\huge~\rm~ x- x+4=3x-x\]
\[\huge~\rm~ 4=3x-x\] 3x-x=?
its y = -x+4 not x+4
ooohhh that makes sense y=-x-4 <---equation 1 y=3x <---equation 2 We know the value of y take equation 1 and plug it into equation 2 \[\huge~\rm~\bf~\color{blue}{ x-4}=3x\] Solve for x Like this?
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