can some check this thx.
yeah good, you can change those to x/3 +1 = y/2 + 1
oh okay thx
\[\frac{ x+3 }{ 3 }=\frac{ x }{ 3 }+\frac{ 3 }{ 3 }\] \[\frac{ y+2 }{ 2 }=\frac{ y }{ 2 }+\frac{ 2 }{ 2 }\] \[\frac{ x }{ 3 }+1=\frac{ y }{ 2 }+1\] \[\frac{ x }{ 3 }=\frac{ y }{ 2 }\]
or if you get stuck, just solve it like normal , as y(x) y in terms of x, then replace x with x/3 y(x/3), y in terms of x/3, but that is more general
okay
i am almost positive this is right but some part of me is saying it might be wrong
my bad need to find the picture
what is not right
this just trying to find the picture sorry
yeh , did you expand that all out and solve for that value?
yes i cross multiply them
it said type a number am i allow to put the negative sign in?
yea, -3 is good 3n^2 - 15n = 3n^2 + n - 18n - 6
thank you
2n = -6, welcome
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