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Mathematics
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OpenStudy (ibrafacts):
can some check this thx.
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OpenStudy (ibrafacts):
OpenStudy (danjs):
yeah good,
you can change those to x/3 +1 = y/2 + 1
OpenStudy (ibrafacts):
oh okay thx
OpenStudy (hossamhoussien):
\[\frac{ x+3 }{ 3 }=\frac{ x }{ 3 }+\frac{ 3 }{ 3 }\]
\[\frac{ y+2 }{ 2 }=\frac{ y }{ 2 }+\frac{ 2 }{ 2 }\]
\[\frac{ x }{ 3 }+1=\frac{ y }{ 2 }+1\]
\[\frac{ x }{ 3 }=\frac{ y }{ 2 }\]
OpenStudy (danjs):
or if you get stuck, just solve it like normal , as y(x) y in terms of x, then replace x with x/3
y(x/3), y in terms of x/3, but that is more general
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OpenStudy (ibrafacts):
okay
OpenStudy (ibrafacts):
i am almost positive this is right but some part of me is saying it might be wrong
OpenStudy (ibrafacts):
my bad need to find the picture
OpenStudy (danjs):
what is not right
OpenStudy (ibrafacts):
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OpenStudy (ibrafacts):
this just trying to find the picture sorry
OpenStudy (danjs):
yeh , did you expand that all out and solve for that value?
OpenStudy (ibrafacts):
yes i cross multiply them
OpenStudy (ibrafacts):
it said type a number am i allow to put the negative sign in?
OpenStudy (danjs):
yea, -3 is good
3n^2 - 15n = 3n^2 + n - 18n - 6
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OpenStudy (ibrafacts):
thank you
OpenStudy (danjs):
2n = -6, welcome
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