When graphing parabolas I know there's a specific way to tell whether to shade the inside or the outside. It depends on which sign you use in your equation(<,>) One means to shade the inside and one means to shade the outside. Does anyone know which goes with which??
I think this might helps http://www.purplemath.com/modules/grphquad2.htm
Thanks! :)
greater than , take any point and see which side of the thing the larger value is, shade above for greater than , and below for less than
If all you're doing is graphing a parabola, you don't shade any part of the graph. If you were told to shade, then you are dealing with an inequality problem.
inside would be the greater than part it opens wider forever, you can say ' above' and 'below' for that , i think
inside the parabola is always a larger value than the value on the curve, for y=x^2
if it is y = -x^2, it opens down, things are opposite, inside that one will be the less than smaller values
Again, where you shade a parabola depends upon the particular inequality you're graphing. Where would you shade\[5x^2-2x +1\le8?\]
Once again: NO SHADING unless you are dealing with an inequality.
Open Up +x^2 greater than values are inside the curve, above less than is everything else, below opens down -x^2 opposite case greater than values are outside the curve, above less than values are inside the curve, below
the parabola represented by \[5x^2-2x +1\le8\] opens up. We know that much. Note that this is an inequality. Which line or curve represents the smallest possible y values? the largest possible y valule?
for any function if it is greater than , the solution region is above the curve if it is less than , then the solution region is below the curve
Thanks for all the help guys! I understand it much better now :)
Dan: Please take a look at this product of Wolfram Alpha: http://www.wolframalpha.com/input/?i=5x%5E2-2x+%2B+1+is+less+than+or+equal+to+8
that is not a function y=f(x)
solve the thing for y if y > shade above the curve y < shade below
oh, that is the solution set for the parabola and the line
y > parabola and y < line results in that region, and in that case you can combine the two things to a single inequality parabola < y < line that is how you write that sort of inequality parabola < line
For just one function , all the area above is greater , all area below is less than compound functions like yours, has shading only where both the parts solution regions overlap and are in common
Join our real-time social learning platform and learn together with your friends!