Question

Can I get some help Simplifying complex fraction (Algebra 2)?

Answer 1

Simplify \[\frac{ 18x-6 }{ 9x^5 }\div \frac{ 15x+5 }{ 21x^2 }\]

Answer 2

you can change division to multiplication \[\large\rm \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} *\frac{d}{c}\]multiply the first fraction by the reciprocal of the 2nd fraction

Answer 3

Oh ok I'm working on the now give me second

Answer 4

\[\frac{ 18x-6 }{ 9x5 }\times \frac{ 21x^2 }{ 15x+5 }\] does this look right?

Answer 5

yes correct now factor the binomial

Answer 6

both of them?

Answer 7

yes.

Answer 8

\[\frac{ 6(3x-1) }{ 9x^5 }\times \frac{ 21x^2 }{ 5(3x-1) }\] is this right?

Answer 9

i think the next step crossing out the 3x-1 since they both have that in common?

Answer 10

that's correct!

Answer 11

So now i have \[\frac{ 6 }{ 9x^5 }\times \frac{ 21x^2 }{ 5 }\]

Answer 12

good what else you can do to simplify ?

Answer 13

get rid of the x's?

Answer 14

how would you do that ?

Answer 15

Look for ways to reduce this expression further. Note that 6, 21 and 9 share a common factor. Also note that \[\frac{ x^2 }{ x^5 }\] can be reduced.

Answer 16

\[\frac{ 2 }{ 3x^3 }\times \frac{ 7 }{ 5 }\]

Answer 17

is this right?

Answer 18

Could you simplify that result further, by multiplying as indicated?

Answer 19

okay so try to write each step thats way you will stay away from any kind of mistake
\[\frac{6 }{ \color{ReD}{3} { \cancel{9}}x^5 }\times \frac{\color{ReD}{ 7} {\cancel{21}}x^2 }{ 5 }\]
now how would you reduce the first fraction ?

Answer 20

\[\frac{ 2 }{ 1x^5 }?\]

Answer 21

is this correct?

Answer 22

that's right
6 divided by 3 would be 2/1
\[\frac{\color{blue}{2}{\cancel{6}} }{ \color{blue}{1}{\cancel{3}} { \cancel{9}}x^5 }\times \frac{\color{ReD}{ 7} {\cancel{21}}x^2 }{ 5 }\]
\[\rm \frac{ 2 }{ 1x^3 } *\frac{7}{5}\]

Answer 23

what do i do from this step?

Answer 24

is there anything else you can cancel out ??

Answer 25

I don't think so?

Answer 26

alright thats it now you can just multiply

Answer 27

would i get \[\frac{ 10 }{ 7x^3 }\]

Answer 28

WAIT WAIT

Answer 29

I SEE MY MISTAKE

Answer 30

good lol

Answer 31

\[\frac{ 14 }{ 5x^3 }\] should be the answer

Answer 32

ye that's correct !! ^^
\[\rm \frac{ a }{ b } *\frac{c}{d} = \frac{a*c}{b*d}\]

Answer 33

good job! :=))

Answer 34

HEYYOOO