Question

balance the following equations:
potassium bromide + chlorine
fluorine + lithium iodide

Answer 1

@Somy

Answer 2

@inkyvoyd

Answer 3

ok do you know how to write out the reactants and products?

Answer 4

yes

Answer 5

so what do i do to balance the first equation

Answer 6

potassium bromide + chlorine
fluorine + lithium iodide
What is the formula for each of the chemicals in the first equation?

Answer 7

kBr2+C2
F+LiI2

Answer 8

is that write?

Answer 9

*right

Answer 10

KBr2?

Answer 11

what charge does a potassium ion hold?

Answer 12

+1

Answer 13

and Bromine?

Answer 14

-1

Answer 15

so what is potassium bromide?

Answer 16

neutral

Answer 17

+1-1

Answer 18

?

Answer 19

yah, I think you rproblem is your notation is wrong... potassium bromide is KBr, but 2 units is 2KBr not KBr2 .. KBr2 refers to one potassium with 2 bromines... always put the number before the molecule to denote how many. Also chlorine is not C, carbon is C... take another guess at what chlorine is :P

Answer 20

is it
2KBr + Cl2 ---> 2KCl + Br2

Answer 21

Yes, looks good. Depending on formality you might want to add states... 2KBr(s)+Cl2(g) etc

Answer 22

ok what about the other one?

Answer 23

fluorine + lithium iodide
... fluorine is not Fl :)

Answer 24

F+LiI2?

Answer 25

LiI2 or 2LiI?

Answer 26

LiI2

Answer 27

F2+LiI2

Answer 28

?

Answer 29

ok F or F_2?

Answer 30

also LiI2 is wrong

Answer 31

i dunno just tell me the answer please

Answer 32

sorry tha't snot allowed here. Let's start over.
fluorine + lithium iodide
What is Fluorine's formula? Lithium iodide?

Answer 33

F and LiI

Answer 34

Fluorine is diatomic...

Answer 35

whats that

Answer 36

F2, not F

Answer 37

ok

Answer 38

F2 + LiI

Answer 39

ok... and the product?

Answer 40

it just says write a balance equation for the reactions below:
fluorine + lithium iodide

Answer 41

ya what do you get when you combine the two?

Answer 42

2FLiI

Answer 43

is that right?

Answer 44

thamks

Answer 45

*thanks

Answer 46

omg

Answer 47

what

Answer 48

no no

Answer 49

it's a single replace reaction

Answer 50

it's wrong

Answer 51

we are talking about a single replacement reaction here... fluorine replaces iodine

Answer 52

it just says balance

Answer 53

@inkyvoyd I think u will have to describe 12ziar from the beginning !

Answer 54

no you balance the equation but you need to know the products and reactants

Answer 55

@Rushwr I think you should do it since I keep making potato mistakes

Answer 56

nah u better do it ! @inkyvoyd Cuz I don't know how to teach these parts LOL

Answer 57

somy somy omy omyomy will do it then

Answer 58

Alright
potassium bromide + chlorine
KBr + Cl2 -> this reaction is a single replacement reaction, which means Cl2 (because it is more electronegative than Br = look at electronegativity table) it will kick out Br and form a bond with K
so result is KCl and Br , now here you gotta balance

same story happens with the other reaction F2 kicks out I from LiI and so you get LiF and I
again balance this reaction

Answer 59

I guess somy has started that already..... she was typing and still is

Answer 60

i am soooo confused now

Answer 61

just follow somyy she is rite

Answer 62

ok

Answer 63

yeah I will help u after that.... If u don't understand somy also

Answer 64

k

Answer 65

she is doing it right up to now ! SO yeah u should be able to understand !

Answer 66

i'll be back soon

Answer 67

I'll give you one example outside your q
NaBr + Cl2 => NaCl + Br2

now lets balance
NaBr + Cl2 => NaCl + Br2
look at Br on right and left side of the arrow
on the right side you have Br2 which means u have 2 Br atoms (Thats a rule, the halogens alone are always a diatomic) but on your left side you have only 1 Br
thus you need to get a number that will make it a 2

2NaBr + Cl2 => NaCl + Br2
so now we added 2 there
and now on the left side we have 2 Na atoms but right side has only one
so again we gotta make it to 2

2NaBr + Cl2 => 2NaCl + Br2

now when you look at Cl on both sides, its same number isnt it?

now for sure u can say that the reaction is balanced

Answer 68

@inkyvoyd what do u think ? any parts to be added ?

Answer 69

lol somyy did a better job than me - I probably shouldn't have been multitasking when trying to help out derp... made two very derpy mistakes

Answer 70

Obviously we make mistakes... Somy is a genius . all hale somy ^_^

Answer 71

in case if you dont know, when you put a number before a compound in a reaction like we did
\(\color {red}{2}\)NaBr
that 2 means you are multiplying 2 to 1 Na atom which now makes it 2 Na atoms
and also you are multiplying Br by 2 and now you get 2 Br atoms
so you basically doubled the amount of atoms in this compound if that makes sense

Answer 72

So I was thinking since 13ziar doesn't know about the displacement reactions......
I thought it to put it on this way !

Answer 73

@13ziar
We have series called the electrochemical series. There the metals and non metals are place according to their reducing or oxidizing ability. Down the electrochemical series the reducing ability decreases and oxidizing ability increases.
I will attach the table

Answer 74

https://en.wikipedia.org/wiki/Standard_electrode_potential_(data_page)

Answer 75

Down the group after hydrogen we will find non metals.
In the non metal side the elements in the latter part of the table can displace the upper ones.
Here in your question we are given with 4 non metals those chlorine, bromine , iodine and fluorine.
I will place them according to the order of the electrochemical series
\[I ^{-}\]
\[Br ^{-}\]
\[Cl ^{-}\]
\[F ^{-}\]

Answer 76

The first reaction you are given with is KBr + Cl2
As you can see Cl is in the latter part of the non metal side of the electrochemical series (remember this is the opposite for metals) and Br^- is up. Therefore Cl^- will displace Bromine. Thus the reaction will be :
KBr + Cl2 ------> KCl + Br2
Now we have a complete reaction, after that you only need to balance.
Note: Most of the halogens are diatomic molecules. So when displaced the other will go to become a diatomic molecule .

Answer 77

I guess I'm right right? @Somy

Answer 78

This might not be a complete answer but I hope it covers the base atleast a little bit ^_^

Answer 79

yeah, you are right, well done :)

Answer 80

oh thanks ! @somy :)

Answer 81

np :D

Answer 82

:D I know this is like a basic very very basic explanation!!! But I hope u can understand @13ziar !

Answer 83

Thanks all

Answer 84

Np

Answer 85

No problem :) @13ziar