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Mathematics 6 Online
OpenStudy (albert0898):

I will fan and medal!

OpenStudy (albert0898):

If \[\log_{a}5 = x \] and \[\log_{a}7 = y \] then \[\log_{a} \sqrt{1.4}\] =

OpenStudy (solomonzelman):

The hint: \(\color{#000000 }{ \displaystyle 7/5=1.4 \quad \Longleftrightarrow \quad \sqrt{7/5}=\sqrt{1.4} }\) And the rules are\( : \) \(\color{#000000 }{ \displaystyle \log_a(b)+\log_a(c)=\log_a(b\cdot c) }\) (1) \({\tiny \\[0.8em]}\) \(\color{#000000 }{ \displaystyle \log_a(b^c)=c\log_a(b) }\) (2)

OpenStudy (solomonzelman):

I forgot to mention, another rule, \(\color{#000000 }{ \displaystyle \log_a(b)-\log_a(c)=\log_a(b\div c) }\) (3)

OpenStudy (albert0898):

Thank you :) I get it now

OpenStudy (solomonzelman):

Ok, so using the rule, you need to make some expression (and modify it as you go) that will get you to \(\log_a(\sqrt{1.4})\)

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