Question

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

https://njvs.desire2learn.com/content/enforced/15358-CO_4636/0507Mod

Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points)


1) By the cross product property, AB2 = BC multiplied by BD.

2) By the cross product property, AC2 = BC multiplied by BD.

3) By the cross product property, AC2 = BC multiplied by AD.

4) By the cross product property, AB2 = BC multiplied by AD.

Answer 1

cant see picture

Answer 2

Please post a screenshot.

Answer 3

let me try again

Answer 4

did that open?

Answer 5

much better :)

Answer 6

yp

Answer 7

yay! :)

Answer 8

Can any of you help me? @Mehek14 @AlexandervonHumboldt2 @pooja195

Answer 9

Oke which one do you think?

Answer 10

I'm pretty lost... I know that you would prove it by AA theorem but idk the cross product property

Answer 11

any choices you can eliminate?

Answer 12

Umm number one?

Answer 13

Just by looking at it BC multiplied by BD seems a lot bigger than AB squared...

Answer 14

But geometric wise I'm at a loss

Answer 15

If I had to guess I would go with number 3 because there are 2 shared angles...

Answer 16

@Mehek14 are you still here?

Answer 17

I would go with the 3rd choice too because the others make no sense

Answer 18

wait- are you sure?

Answer 19

Can you explain it at all?

Answer 20

I'm honestly confused

Answer 21

:( Are there any other qualified helpers who know this? I don't want to waste my owl bucks

Answer 22

@dan815 @sleepyjess

Answer 23

@pooja195 @Hero @Jaynator495

Answer 24

@triciaal

Answer 25

I'm sorry, and I understand that you don't want to waste your OwlBucks, but we can't help on test questions, as that would be considered cheating and could get us both suspended :(

Answer 26

However it is not a test question... I'm doing practice problems and I'm just super stuck

Answer 27

Please understand I'm not trying to accuse you, but I noticed the link says "ModuleFiveExamPartOne"...

Answer 28

I don't know if you can read the whole thing but its the practice test for the exam. I understand what you saw now... It says "modulefiveexampartonepracticetest" but its cut off

Answer 29

We have \[\frac{ AB }{ CB} = \frac{ AD }{ AB }\] and \[\frac{ AC }{ BC } = \frac{ AD }{ AC }\] from what we get from similar triangles, and you should be simply able to write these ratios as products (which tend to come from cosines and sines)
Please try the rest yourself, you may look up proof of similar triangles for pythagorean theorem for more information. Hope that helps!

Answer 30

I have no idea what half of that means... cosines? sines? I looked everything up but i got desperate enough to come and pay for help :( My teacher will take too long to respond and I just want to study for the real exam Im taking tomorrow

Answer 31

You will have to sum the two quantities, I must go now, but you may find this of use as it takes a similar approach, please look: https://en.wikipedia.org/wiki/Pythagorean_theorem

Answer 32

I know the pythagorean theorem- I need help with the cross conduct property...

Answer 33

Please if you scroll down, but I really have to go, here is what I wanted you to see you can see the full image by scrolling down on that wikipedia page.

Answer 34

@Mehek14 @sleepyjess @QuantumMechanics I am very disappointed and frustrated with this service. I paid for immidiate help and its been 40 minutes and accusations. I was lead to a wikipedia page, which I have already read for free. I have wasted 40 minutes of study time and money for absolutely nothing. I'm sorry to say that I will be filing a complaint on this inadequate service. Being polite does not make up for wasting my time and money. Open study just lost a costumer and all that costumers friends and family.

Answer 35

I actually tried helping. I have not accused you of anything. I tried my best.

Answer 36

I'm sorry, I wasn't sure how to do this question. I wasn't trying to accuse you, just ask why the link said that it was from a test. :(

Answer 37

Please email complaints@openstudy.com if you would like to try to get a refund.

Answer 38

http://prntscr.com/9ollh7 need authorization in order to help you.

Answer 39

Hi again, I actually had answered your question and all it requires now is a little algebric manipulation as all the properties which were asked in your question were the same, the site I had linked also showed a similar method that of your question.

But as you have deleted your post I do recall sleepyjess is correct the link in itself suggested a exam. Please do not blame others for your faults.

Answer 40

yay