Question

12y+8 = 5y+2 What is the answer every time I do it will not work?

Answer 1

Subtract 5y from both sides and tell me what you get.

Answer 2

7y+8=2

Answer 3

yes, very nice!

Answer 4

Yes

Answer 5

Now, you would like to isolate the term that contains "7y", right?
But, you have +8 on the same side.

What should you do (to/from both sides) to get 7y by itself?

Answer 6

subtract 8

Answer 7

7y=-6

Answer 8

Yes, subtract 8 from both sides, and this gives you?

Answer 9

Am I not right @solomonzelman

Answer 10

I am not trying to take over, but doing user's work is inappropriate according to the site's policy.

Answer 11

Please am just trying to learn also

Answer 12

its cool guys

Answer 13

I can back off if u want me to

Answer 14

yes, 7y=-6
is correct.

Answer 15

its ok with me i was just confused for a little bit there on what you said daniel56k

Answer 16

Now, you want to finish solving for y.
y is multiplied times 7, (so you have 7 times y),
and you want to get y on its own.

What do you do to both sides to get rid of that 7 multiplied times y?

Answer 17

divide

Answer 18

Yes, and what would you divide both sides by, to get rid of the 7 multiplied on y?

Answer 19

a really long decimal number but how is that a variable?

Answer 20

we have
7y=-6

try to divide both sides by 7 (is tat what you did?)

Answer 21

you can write the right side as a fraction

Answer 22

yea y= 0.855714286

Answer 23

but you had a NEGATIVE 6

Answer 24

yea i still get same answer

Answer 25

-6/7 = -0.855714286

Answer 26

you get negative that, because you are dividing negative by positive.

Answer 27

7y = -6

we divided both sides by 7,

7y ÷ 7 = -6 ÷ 7

and we get,

y = -6/7

Answer 28

I am writing the answer as a fraction, because that is more precise, more convenient. just better.

You don't have to find the decimal equivalent to the fraction.

Answer 29

ok what i am not getting is why there is a decimal as a variable

Answer 30

Maybe you meant -
why we get a solution for y, that is a decimal?

Answer 31

(your wording is a little hard to understand)

Answer 32

ok what i am not getting is why there is a decimal as a variable

Answer 33

yea thats what i meant sorry

Answer 34

There isn't anything wrong with that.
You get a decimal/fraction.

Answer 35

If you get a decimal/fraction, whether negative or positive, then that isn't an automatically faulty result; you know what I mean?

y = some decimal
is not an indication of an error

Answer 36

And why we get a decimal, is because we have arrived at that solution after preforming the proper steps.

Do you have any questions about the steps we did to solve the problem?

Answer 37

no so the decimal is the answer and if so how would you simplify it?

Answer 38

Example: \(\color{#000000 }{ \displaystyle 5z-9=3z+10 }\)

Subtract \(3z\) from both sides,

\(\color{#000000 }{ \displaystyle 5z-9\color{red}{-3z}=3z+10\color{red}{-3z} }\)

I know that: 5z-3z=2z
3z-3z=0

(3z on the right cancel themselves out)
And you get the following equation,

\(\color{#000000 }{ \displaystyle 2z-9=10 }\)

Now, I will add 9 to both sides,
\(\color{#000000 }{ \displaystyle 2z-9\color{red}{+9}=10\color{red}{+9} }\)

I know that: 10+9=19
-9+9=0

(9 on the left cancel themselves out)
And you get,

\(\color{#000000 }{ \displaystyle 2z=19 }\)

then, we will divide both sides by 2, to solve for z.
\(\color{#000000 }{ \displaystyle 2z\color{red}{\div 2}=19\color{red}{\div 2} }\)

and I get, ((improper fraction))
\(\color{#000000 }{ \displaystyle z=19/2 }\)
(it's called improper fraction becase numerator is bigger then denominator)

you can also record your result as, ((decimal))
\(\color{#000000 }{ \displaystyle z=9.5 }\)

and also, ((mixed fraction))
\(\color{#000000 }{ \displaystyle z=9\frac{1}{2} }\)

Answer 39

@clarkgrace you know about fractions, correct?
(look at the example later, please not now)

Answer 40

to late

Answer 41

what do you mean?
you got to go?

Answer 42

oh no i had already looked at the example problems