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Mathematics 19 Online
OpenStudy (anonymous):

Always True, Sometimes True, or Never True? Please help! (will MEDAL AND FAN)

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 Would you help please?

OpenStudy (anonymous):

@campbell_st quick help?

OpenStudy (campbell_st):

ok... so for the 1st question can you have an equation such as \[y = x^2 + 4\] will it have real solutions... given it has real coefficients?

OpenStudy (campbell_st):

this also helps with the 2nd question as this polynomial doesn't cut the x- axis... its a positive definite parabola

OpenStudy (campbell_st):

given we can't give answers, the example above should head you in the right direction.

OpenStudy (anonymous):

@campbell_st when I graphed the first equation you gave me it doesn't touch the X axis at all..

OpenStudy (campbell_st):

so it has real coefficients and no real roots.... so which choice do you think is best..?

OpenStudy (anonymous):

Sometimes true for the first one correct?

OpenStudy (triciaal):

i would agree

OpenStudy (anonymous):

Okay Lets go onto the second one?

OpenStudy (triciaal):

what do you think based on the response of @campbell_st

OpenStudy (campbell_st):

so the 2nd question you graphed \[y = x^2 + 4\] did it cut the x-axis... does it have real or complex roots..?

OpenStudy (anonymous):

didn't cut the X axis @campbell_st

OpenStudy (campbell_st):

so are the solutions complex or real..?

OpenStudy (campbell_st):

set y = 0 and solve \[x^2 + 4 = 0\] will the answer be real numbers or complex numbers...

OpenStudy (anonymous):

Real numbers

OpenStudy (anonymous):

wait, complex numbers sorry

OpenStudy (campbell_st):

well \[x^2 = -4\] so \[x = \sqrt{-4}\] you need to identify that you can't take the square root of a negative number you need the complex identity \[i^2 = -1\] so the problem is now \[x = \sqrt{4i^2} = \pm 2i\] so any thoughts on the correct answer

OpenStudy (campbell_st):

complex is correct so the 1st choice looks good

OpenStudy (campbell_st):

the last one... I'd choose the 1st option...

OpenStudy (anonymous):

Okay I see what you did thanks a lot!

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