Question

if 1.01g of hydrogen(H) combines with 16.0g of oxygen (O), how many grams of hydrogen will be needed to combines with the same amount of oxygen to form H2O?

Answer 1

What do u think the answer is ?

Answer 2

17.01 @Rushwr

Answer 3

Show me ur work ?

Answer 4

16.0+1.01=17.01

Answer 5

okai I will show u the work.
We need one equation here
n= m/M
n - no. of moles
m= mass
M= molar mass

S in the first part they say 1.01g of H combines with 16g of O
no we will find the moles in each. ( this is not necessary since u seem to be confused only )
no. of moles of H = 1.01 /1.01 = 1 mole
no. of moles of O = 16/16= 1 mole
( molar mass of O and H u have to know )

TO form H2O you need one mole of O and 2 moles of H.
We know the moles of O present 16g (we found it earlier , 1mole)
(moles of H = twice the no. of moles of O )
So now use the same equation for H
We know the moles , molar mass and we have to find the mass
If n= m/M
then m = n * M right?
So m = 2 * 1.01 = 2.02g

Answer 6

Oh...thank so much @Rushwr

Answer 7

U got it right ?

Answer 8

Yes

Answer 9

okai then have a nice day ^_^

Answer 10

You too @Rushwr