Question

@dan815

Answer 1

hm

Answer 2

do you know how to do it?

Answer 3

not really

Answer 4

try taking a loook at the line of best fit, see the differences from the expected to real

Answer 5

is it the difference between the values?

Answer 6

in any case if you don't know how to do this may I ask for another person's help? Im asking because I don't want to offend you by asking someone else since you have helped me

Answer 7

@dan815 ?

Answer 8

oh no ofcourse, go ahead

Answer 9

alright thank you @ParthKohli

Answer 10

@ganeshie8

Answer 11

@mathmate @mathmale

Answer 12

@Michele_Laino

Answer 13

I think that we have to compute the relative change going from one reading level to the subsequent reading level, and then we have to compute the average value from the values so obtained. For example, we have this first relative change:
\[{r_1} = \frac{{5.5 - 4.8}}{{7.2 - 5.1}} \cdot 100 = 33.3\% \]
so, please do the same for other reading levels

Answer 14

next, we have:
\[{r_2} = \frac{{6.1 - 5.5}}{{6.3 - 7.2}} \cdot 100 = - 66.6\% \]

Answer 15

would it help if I gave you my options?

Answer 16

yes!

Answer 17

78.5%
88.7%
92.2%
81.5%

Answer 18

hey how can i help

Answer 19

@Michele_Laino is already helping but you can help me on my next question if you'd like :)

Answer 20

with my procedure, I got \(83\%\)

Answer 21

ok bye

Answer 22

alright thank you :)
and the closest value is 85

Answer 23

please keep in mind that you have to compute an average value of the percentages obtained, namely an arithmetic average

Answer 24

how do I do that?

Answer 25

@Michele_Laino

Answer 26

it is simple. From my method above, I got the subsequent percentages:
\[\begin{gathered}
{r_1} = \frac{{5.5 - 4.8}}{{7.2 - 5.1}} \cdot 100 = 33.3\% ,\quad {r_2} = \frac{{6.1 - 5.5}}{{6.3 - 7.2}} \cdot 100 = - 66.6\% \hfill \\
\hfill \\
{r_3} = \frac{{7.9 - 6.1}}{{8.5 - 6.3}} \cdot 100 = 82\% ,\quad {r_4} = \frac{{6.2 - 7.9}}{{7.7 - 8.5}} \cdot 100 = 213\% \hfill \\
\hfill \\
{r_5} = \frac{{7.9 - 6.2}}{{9.3 - 7.7}} \cdot 100 = 106\% ,\quad {r_6} = \frac{{4.3 - 7.9}}{{5 - 9.3}} \cdot 100 = 84\% \hfill \\
\hfill \\
{r_7} = \frac{{6.1 - 4.3}}{{6.4 - 5.0}} \cdot 100 = 129\% \hfill \\
\end{gathered} \]

Answer 27

so I compute the average percentage, like below:
\[\bar r = \frac{{33 - 66 + 82 + 213 + 106 + 84 + 129}}{7} = 83\% \]

Answer 28

that makes a lot of sense I will revise it in case there was some mistake in the calculation that is not allowing a result from the choices to appear

Answer 29

ok! :)

Answer 30

I got 83% as well

Answer 31

so I guess I will go with 85 since is more similar @Michele_Laino

Answer 32

among the options you provided, I don't see 88%

Answer 33

oops.. I meant I don't see 85%

Answer 34

78.5%
88.7%
92.2%
85.1%
yeah lol my bad

Answer 35

ok! I think that, if my procedure is the right one, then we can choose 85.1%

Answer 36

alright thank you very much :)

Answer 37

:)

Answer 38

and you were correct thank you sooooo much :) are available to help me with more problems please?

Answer 39

@Michele_Laino

Answer 40

ok!

Answer 41

alright thank you :)

Answer 42

@Daniellelovee
Have you done linear regression yet? It is the so called "best" line that passes through or near all the data points, using least squares.
I have calculated the linear regression line which most people use to "predict" values, and the slope of the regression line is 77.9%.
This might be useful if you have already done linear regression lines.