Question

MEDALS

Answer 1

The table below shows the height (in inches) and weight (in pounds)of eight basketball players.

Height=67, 69, 70, 72, 74, 74, 78, 79
Weight=183, 201, 206, 220, 226, 240, 253, 255

what is the correlation of the set of data? Round your answer to the nearest thousandth.
A.-0.946
B.0.596
C.0.035
D.0.981

Answer 2

Can you help me, @callielovesyhuu

Answer 3

@Michele_Laino

Answer 4

@pooja195

Answer 5

FREE?

Answer 6

we have to apply the corresponding formula

Answer 7

free medals

Answer 8

Oh there is a question >.<

Answer 9

._.

Answer 10

free medals

Answer 11

No free medal you get one if you answer my question CORRECTLY

Answer 12

If I call with \(x\) the height, and with \(y\) the weight, then I'm searching for a correlation: height---> weight
so, here is the formula for the correlation coefficient \(r\)

Answer 13

\[\Large r = \frac{{\sum {\left( {{x_i} - \bar x} \right)\left( {{y_i} - \bar y} \right)} }}{{{{\left\{ {\sum {{{\left( {{x_i} - \bar x} \right)}^2} \times \sum {{{\left( {{y_i} - \bar y} \right)}^2}} } } \right\}}^{1/2}}}}\]

Answer 14

where:
\[\Large \bar x = \frac{{\sum {{x_i}} }}{N},\quad \bar y = \frac{{\sum {{y_i}} }}{N},\quad N = 8\]
so, the first step, is to compute, both \({\bar x}\) and \({\bar y}\)

Answer 15

I have a lot to do so could you hurry up

Answer 16

what you are typing is making no since to me

Answer 17

such formulas, are the standard formulas in order to compute the requested coefficient of correlation

Answer 18

What is my answer?

Answer 19

I think it is B

Answer 20

please, I have indicated the right way, and now you have to do such computation on your own

Answer 21

I. DO. NOT. UNDERSTAND.

Answer 22

I have told you that

Answer 23

I'm sorry, I can't give the direct answer, since it is against the code of conduct

Answer 24

I can guide you, step by step, to the final answer

Answer 25

Type it out and i will read it

Answer 26

please, try to compute the mean values of x, and y, using these formulas:
\[\bar x = \frac{{\sum {{x_i}} }}{N},\quad \bar y = \frac{{\sum {{y_i}} }}{N},\quad N = 8\]
wherein the x's are the heights, and the y's are the weights

Answer 27

i dont understand for the third time

Answer 28

for example, we have this:
\[\begin{gathered}
\bar x = \frac{{\sum {{x_i}} }}{N} = \hfill \\
\hfill \\
= \frac{{67 + 69 + 70 + 72 + 74 + 74 + 78 + 79}}{8} = ...? \hfill \\
\end{gathered} \]

Answer 29

72. 875

Answer 30

that's right!
similarly, we can write this:
\[\begin{gathered}
\bar y = \frac{{\sum {{y_i}} }}{N} = \hfill \\
\hfill \\
= \frac{{183 + 201 + 206 + 220 + 226 + 240 + 253 + 255}}{8} = ...?\quad \hfill \\
\end{gathered} \]

Answer 31

210.625

Answer 32

please, retry, I got
\[\bar y = 223\]

Answer 33

ok i mixed up a number

Answer 34

What is my answer

Answer 35

Is it C?

Answer 36

now, we have to do such computations:
\[\begin{gathered}
\sum {\left( {{x_i} - \bar x} \right) = } \hfill \\
\hfill \\
= \left( {67 - 72.875} \right) + \left( {69 - 72.875} \right) + \left( {70 - 72.875} \right) + \hfill \\
\hfill \\
+ \left( {72 - 72.875} \right) + \left( {74 - 72.875} \right) + \left( {74 - 72.875} \right) + \hfill \\
\hfill \\
+ \left( {78 - 72.875} \right) + \left( {79 - 72.875} \right) = ...? \hfill \\
\end{gathered} \]

Answer 37

and:
\[\begin{gathered}
\sum {\left( {{y_i} - \bar y} \right)} = \hfill \\
\hfill \\
= \left( {183 - 223} \right) + \left( {201 - 223} \right) + \left( {206 - 223} \right) + \hfill \\
\hfill \\
+ \left( {220 - 223} \right) + \left( {226 - 223} \right) + \left( {240 - 223} \right) + \hfill \\
\hfill \\
+ \left( {253 - 223} \right) + \left( {255 - 223} \right) = ...? \hfill \\
\hfill \\
\end{gathered} \]

Answer 38

-260

Answer 39

please wait, I'm checking such result...

Answer 40

I think my answer is C tho

Answer 41

I got a different value for \[\sum {\left( {{x_i} - \bar x} \right)} \]

Answer 42

what is it

Answer 43

in order to compute the numerator, we have to evalate this quantity:
\[\begin{gathered}
\sum {\left( {{x_i} - \bar x} \right)\left( {{y_i} - \bar y} \right)} = \hfill \\
\hfill \\
= \left( {67 - 72.875} \right) \cdot \left( {183 - 223} \right) + \left( {69 - 72.875} \right) \cdot \left( {201 - 223} \right) + \hfill \\
\hfill \\
+ \left( {70 - 72.875} \right) \cdot \left( {206 - 223} \right) + \left( {72 - 72.875} \right) \cdot \left( {220 - 223} \right) + \hfill \\
\hfill \\
+ \left( {74 - 72.875} \right) \cdot \left( {226 - 223} \right) + \left( {74 - 72.875} \right) \cdot \left( {240 - 223} \right) + \hfill \\
\hfill \\
+ \left( {78 - 72.875} \right) \cdot \left( {253 - 223} \right) + \left( {79 - 72.875} \right) \cdot \left( {255 - 223} \right) = ...? \hfill \\
\end{gathered} \]

Answer 44

evaluate*

Answer 45

Check you PM box @Michele_Laino please

Answer 46

I'm very sorry, OpenStudy is a learning website, as we can see fro the Code of Conduct:
"Don't provide someone with just the answer - explain the process, and help guide them through \(understanding\) the problem."

Answer 47

from*