Harry can rake the leaves in the yard 8 hours faster than his little brother Jimmy can. If they work together, they can complete the job in 3 hours. Using complete sentences, explain each step in figuring out how to determine the time it would take Jimmy to complete this job on his own.
@johnweldon1993
\(\dfrac{1}{time~person ~1 ~does ~job} + \dfrac{1}{time ~person ~2~does ~job} = \dfrac{1}{time ~both ~people ~do ~job ~together}\)
\[\frac{ 1 }{ x } + \frac{ 1 }{ 8x } = \frac{ 1 }{ 3 }\]
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This is how you think of these combined work problems. Person 1 does the job in x hours. Person 2 does the job in x - 8 hours. Together they do the job in 3 hours.
ohhhhh so 1/x + 1/x-8 = 1/3
In 1 hour, person 1 does 1/x of the job. In 1 hour, person 2 does \(\dfrac{1}{x - 8} \) of the job. In 1 hour, together, they do 1/3 of the job.
"Harry can rake the leaves in the yard 8 hours faster than his little brother Jimmy can. " Suppose Jimmy can rake the leaves in j hours, then he rakes 1/j of the leaves each hour. Harry can rake the leaves in j-8 hours, so he rakes 1/(j-8) of the leaves each hour. Working together, they rake 1/j + 1/(j-8) of the leaves each hour. "If they work together, they can complete the job in 3 hours." ⅓ of the job is completed per hour. Therefore, 1/j + 1/(j-8) = ⅓ Solve for j: 1/j + 1/(j-8) = ⅓ 3(j-8) + 3j = j(j-8) 3j - 24 + 3j = j² - 8j j² -14j + 24 = 0 j = 12
When you add the work of the two people in 1 hour, it euqlas the work together in 1 hour. \(\dfrac{1}{x}+ \dfrac{1}{x - 8} = \dfrac{1}{3} \)
^equals
BTW, @Gabylovesyou , do you understand why Harry's time is x - 8, and not 8x? Harry is faster. Jimmy is slower. Jimmy takes x hours to do the job. Harry is 8 hours faster, so Harry takes 8 hours less. 8 less than x is x- 8 In this case, x is the time Jimmy takes. x - 8 is the time Harry takes.
oh ok... and how do i solve it ?
i sent u the answer gaby
i still need a clearer explanation on how to solve it.. ;/ @mathstudent55 thank you tho @Cj_2COOL
oh okay
no problem
Jimmy does the job in x hours. In 1 hour, Jimmy does 1/x of the job. Harry works 8 hours faster, so Harry only takes x - 8 hours to do the job. In 1 hour, Harry does 1(x - 8) of the job. When working together, they take 3 hours to do the job, so working together, they do 1/3 of the job in 1 hour. When they work together, in 1 hour they do a combined 1/x + 1/(x - 8) of the job. We know that when working together they do 1/3 of the job in 1 hour, so we combine these two expressions to get \(\dfrac{1}{x} + \dfrac{1}{x - 8} = \dfrac{1}{3} \) Now we need to solve the equation to find how long Jimmy takes to do the job. Then Harry takes 8 hours less.
The reason Harry's time is x - 8 and not 8x is that we are told Harry is 8 hours faster than Jimmy. 8 hours faster means he takes 8 hours less. That means if the slower brother takes x hours, the faster brother takes 8 less hours, and 8 less than x is x - 8. If one brother were 8 times faster than the other brother, then if the faster brother takes x hours, the slower brother would tale 8x hours. There is a big difference between "8 hours faster" and 8 times faster". We have 8 hours faster.
Now we can work on the equation, if you'd like.
yes :) @mathstudent55
\(\dfrac{1}{x} + \dfrac{1}{x - 8} = \dfrac{1}{3}\) The LCD of the 3 fractions is 3x(x - 8). We multiply both sides of the equation by the LCD to get rid of denominators. \(3x(x - 8)\dfrac{1}{x} + 3x(x - 8)\dfrac{1}{x - 8} = 3x(x - 8)\dfrac{1}{3}\) \(3\cancel{x}(x - 8)\dfrac{1}{\cancel{x}~1} + 3x\cancel{(x - 8)}\dfrac{1}{\cancel{x - 8}~1} = \cancel{3}x(x - 8)\dfrac{1}{\cancel{3}~1}\) \(3(x - 8) + 3x = x(x - 8)\) \(3x - 24 + 3x = x^2 - 8x\) \(x^2 - 14x + 24 = 0\) \((x - 2)(x - 12) = 0\) x = 2 or x = 12 In our case, x = 2 does not make sense for Jimmy's time because then Harry's time would be 2 - 8 = -6 hours, and he cannot do a job in negative time. The answer x = 12 makes sense. x is Jimmy's time. Jimmy takes 12 hours to to the job. Harry takes 12 - 8 = 4 hours.
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