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A child and a sled with a combined mass of 50.0kg slide down a frictionless slope. If the sled starts from rest and has a speed of 3.00m/s at the bottom, what is the height of the hill?
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change in kinetic energy is going to equal change in gravitational potential energy.\[\Delta K=1/2 mv^2\] \[\Delta U_g=mg \Delta x\]
Which numbers would I plug into the equation @gollywolly
\[1/2(50.0)(3.00)^2=(50.0)(9.81)\Delta x\]
Thank you so much! @gollywolly
No problem. Do you understand why that works? @daisy_arlene
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Yeah, somewhat @gollywolly
U can solve this problem in another way
v^2=u^2+2gh
h=?
Given u=0
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v=3m/s
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